Answer:
d and a
Step-by-step explanation:
Answer:
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Options:
A) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
B) Reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
D) Reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Explanation:
The null hypothesis H0: µ=43°F (a true mean temperature maintained by refrigerator is equal to 43°)
The alternative hypothesis Ha: µ<>43 (a true mean temperature maintained by refrigerator is not equal to 43).
A type II error does not reject null hypothesis H0 when it is false. Therefore, the type II error for the test fails to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Answer: option d.
Step-by-step explanation:
If <em>y </em>varies directly as <em>x</em> and <em>z</em>, the form of the equation is:
Where<em> k</em> is the constant of variation.
If y=4 when x=6 and z=1 then substitute these values into the expression and solve for <em>k:</em>
<em> </em>Substitute the value of <em>k</em> into the expression. Then, the equation is:
To find the value of <em>y </em>when x=7 and z=4, you must substute these values into the equation. Therefore you obtain:
<em> </em>
Add 3 standard deviations above and below the mean to get the range in which 99.7% of the data in a normal distribution will fall
6.5 + 4.5 = 11
6.5 - 4.5 = 2
So 2 to 11 ounces would be the interval
