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maw [93]
3 years ago
11

PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!

Physics
1 answer:
Solnce55 [7]3 years ago
4 0
It’s B can I have twenty points
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Reactance Frequency Dependence: Sketch a graph of the frequency dependence of a resistor, capacitor, and inductor. RLC Circuit R
jolli1 [7]

Answer:

f=\frac{1}{2\pi \sqrt{LC}}

Explanation:

We know that impedance of a RLC circuit is given by Z=R+J(X_L-X_C)

So Z=\sqrt{R^2+(X_L-X_C)^2} here R is resistance X_L is inductive reactance and X_C is capacitive reactance

To minimize the impedance X_L-X_C should be zero we know that X_L=\omega L\ and \ X_C=\frac{1}{\omega C}

So \omega L-\frac{1}{\omega C}=0

\omega ^2=\frac{1}{LC}

\omega =\sqrt{\frac{1}{LC}}

We know that \omega =2\pi f

So \omega =2\pi f=\frac{1}{\sqrt{LC}}

f=\frac{1}{2\pi \sqrt{LC}}

Where f is resonance frequency  

8 0
3 years ago
What type of reaction requires the greatest energy to get started? A. fusion B. fission C. physical D. chemical
Vilka [71]
What do u mean by that

4 0
3 years ago
Read 2 more answers
Pendulum Swing. You pull a simple pendulum that is 0.240 m long to the side through an angle 3.5◦ and release it.
BigorU [14]

The 'period' of a pendulum . . . the time it takes to go back and forth once, and return to where it started . . . is

T = 2π √(length/gravity)

For this pendulum,

T = 2π √(0.24m / 9.8 m/s²)

T = 2π √0.1565 s²

T = 0.983 second

If you pull it to the side and let it go, it hits its highest speed at the BOTTOM of the swing, where all the potential energy you gave it has turned to kinetic energy.  That's 1/4 of the way through a full back-and-forth cycle.

For this pendulum, that'll be (0.983s / 4) =

<em>(A). T = 0.246 second</em>   <em><===</em>

<em></em>

Notice that the formula T = 2π √(length/gravity) doesn't say anything about how far the pendulum is swinging.  For small angles, it doesn't make any difference how far you pull it before you let it go . . . the period will be the same for tiny swings, little swings, and small swings.  It doesn't change if you don't pull it away too far.  So . . .

<em>(B).</em>  The period is the same whether you pulled it 3.5 or 1.75 . <em>T = 0.246 s.</em>  

5 0
4 years ago
Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equ
Irina-Kira [14]

Answer:

Magnitude of the net force on q₁-

Fn₁=1403 N

Magnitude of the net force on q₂+

Fn₂= 810 N

Magnitude of the net force on q₃+

Fn₃= 810 N

Explanation:

Look at the attached graphic:

The charges of the same sign exert forces of repulsion and the charges of   opposite sign exert forces of attraction.

Each of the charges experiences 2 forces and these forces are equal and we calculate them with Coulomb's law:

F= (k*q*q)/(d)²

F= (9*10⁹*3*10⁻⁶*3*10⁻⁶)(0.01)² =810N

Magnitude of the net force on q₁-

Fn₁x= 0

Fn₁y= 2*F*sin60 = 2*810*sin60° = 1403 N

Fn₁=1403 N

Magnitude of the net force on q₃+

Fn₃x= 810- 810 cos 60° = 405 N

Fn₃y= 810*sin 60° = 701.5 N

Fn_{3} = \sqrt{405^{2}+701.5^{2}  }

Fn₃ = 810 N

Magnitude of the net force on q₂+

Fn₂ = Fn₃ = 810 N

6 0
3 years ago
What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
olya-2409 [2.1K]

Answer:

hot humid with lots of rain.

Explanation:

ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.

5 0
4 years ago
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