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artcher [175]
3 years ago
14

A spindle connects two wheels with fixed axles by a fan belt. If the effort wheel is larger than the resistance wheel, which axl

e will turn faster?
A. the effort axle
B. the resistance axle
C. Both axles turn at the same rate.
D. The wheel size does not affect the axle-turning rate.
Physics
1 answer:
MariettaO [177]3 years ago
8 0
Power = Iω (constant) as they are connected together, since effort axle has large radius than resistance axle, so moment of inertia of effort axle is also more as compared to resistance axle, so angular speed of effort axle is less than the resistance axle. So answer is B. resistance axle  will have more angular speed as its moment of inertia is less for the same power.
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If a 1.3 kg mass stretches a spring 4 cm, how much will a 5.8 kg mass stretch the
Likurg_2 [28]

Answer:

17.8cm

Explanation:

1.3kg --> 4cm

1kg --> 3, 1/13cm

5.8kg --> 18.8cm

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3 years ago
Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d
Mumz [18]

Answer:

Part a)

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Explanation:

Red car

mass = 1000 kg

speed = 10 m/s

Yellow car

mass = 2000 kg

speed = 5 m/s

Blue car

mass = 500 kg

speed = 20 m/s

Light Blue car

mass = 1000 kg

speed = 20 m/s

Green car

mass = 500 kg

speed = 10 m/s

Purple car

mass = 4000 kg

speed = 5 m/s

Part a)

Now we know that momentum of each car is product of mass and velocity

so we will have

Red Car

P_1 = m v

P_1 = (1000)(10)

P_1 = 10^4 kg m/s

Yellow Car

P_2 = m v

P_2 = (2000)(5)

P_2 = 10^4 kg m/s

Blue Car

P_3 = m v

P_3 = (500)(20)

P_3 = 10^4 kg m/s

Light Blue Car

P_4 = m v

P_4 = (1000)(20)

P_4 = 2\times 10^4 kg m/s

Green Car

P_5 = m v

P_5 = (500)(10)

P_5 = 5 \times 10^3 kg m/s

Purple Car

P_6 = m v

P_6 = (4000)(5)

P_6 = 2\times 10^4 kg m/s

So the momentum is given as

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Force is defined as rate of change in momentum

Now let say all cars will stop in same time interval

so we will have

Force = \frac{impulse}{time}

so we will have

force is in same order as that of impulse

so it is given as

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

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Your order is correct here.

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