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3 years ago

The following quantities describe location or its change:position, distance, and a displacement. Which are vectors?

Physics

2 answers:

-Dominant- [34]3 years ago

6 0

As per the question there are three physical quantities named as position,distance and displacement.

Before coming into a conclusion first we have to understand a vector and a scalar.

A scalar quantity is a quantity which has only magnitude for it's complete specifications.

A vector is a quantity which has magnitude as well as direction and at the same time it is in accordance with the paraellogram law of vector addition.

Out of the three options displacement and position are vector quantities.It is because it is the minimum distance between two points .It has magnitude as well as direction.

Distance can not be considered as a vector quantity as it has only magnitude.There is no specific directions of distance travelled.

Position vector is a vector which provides location of an object in a plane or space.It is nothing else except the point which has x,y,z coordinates with origin is taken as the reference point.

Hence position and displacement are vectors

Tju [1.3M]3 years ago

6 0

Answer:

position and displacement

Explanation:

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A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?

irinina [24]

Answer:

18 m

Explanation:

Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s

solving for the final velocity, v

v = a * t

v = 4 m/s^2 * 3 s

v = 12 m / s

Solving for the average velocity. avg v

avg v = (vo + v) / 2

avg v = (0 m / s + 12 m/s) / 2

avg v = 6 m / s

Solving for the distance traveled after 3 s

d = avg v * t

d = 6 m / s * 3 s

d = 18 meters

In the first 3s the car travels 18 meters.

4 0

3 years ago

PLEASEE I NEED HELP FAST!!! .Study the scenario.A small container of water with a low temperature is poured into a large contain

RSB [31]

Answer:

that best describes the process is C

Explanation:

This problem is a calorimeter process where the heat given off by one body is equal to the heat absorbed by the other.

Heat absorbed by the smallest container

Q_c = m ce ( $T_{f}$ -T₀)

Heat released by the largest container is

Q_a = M ce (T_{i}-T_{f})

how

Q_c = Q_a

m (T_{f}-T₀) = M (T_{i} - T_{f})

Therefore, we see that the smaller container has less thermal energy and when placed in contact with the larger one, it absorbs part of the heat from it until the thermal energy of the two containers is the same.

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8 0

4 years ago

FIRST ANSWER IS BRAINIEST TAKE YOUR TIME I NEED RIGHT ANSWERS FIRST ANSWER IS BRAINIEST ANSWER TAKE YOUR TIME NEED RIGHT ANSWER

V125BC [204]

A = 7
B = 4
C = 5
D = 9
E = 8
F = 1
G = 2
H = 10
I = 6
J = 3

4 0

3 years ago

Read 2 more answers

3. a) If the distance between two objects increases by a factor of 5 (5),

irina [24]

Answer:

Answer for A

Explanation:

F1=GmM/r1^2

If r2 becomes r2=5r

F2=GmM/(25r^2)

Multiply with 25 gives to maintain the same force

I.e.,25F2=F1

F2=G(25m)M/25r^2=F1

By the factor 25 would change to increase to same.

3 0

2 years ago

An object is traveling on a circle with a radius of 6 feet. If in 80 seconds a central angle of 9/4 radians is swept out, then f

trapecia [35]

Answer:

The angular speed of the object is 0.0281 rad/s

The linear speed of the object is 0.169 ft/s

Explanation:

Given;

radius of the circle, r = 6 ft

time of motion of the object around the circle, t = 80 s

central angle formed by the object during the motion, θ = 9/4 rad = 2.25 rad

The angular speed of the object is calculated as;

$\omega = \frac{\theta }{t} = \frac{2.25 \ rad}{80 \ s} = 0.0281 \ rad/s$

The linear speed of the object is calculated as;

v = ωr

v = 0.0281 rad/s x 6ft

v = 0.169 ft/s

8 0

3 years ago