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wariber [46]
3 years ago
5

A 0.750 kg ball is thrown vertically upward with an initial speed of 5.00 m/s. If the altitude at which the ball is defined to h

ave zero gravitational potential energy is 1.00 m below its initial position, a simple calculation shows that its initial gravitational potential energy is 7.35 J. What is the ball's gravitational potential energy at 0.50 m above its initial position
Physics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

12.267367282991963672828w9

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Light passes from a material A, which has an index of refraction of 4/3, into material B, which has an index of refraction of 5/
katrin2010 [14]

Answer:

(b) 32.2°

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 30.0° )

{\theta_r} is the angle of refraction  ( ? )

{n_r} is the refractive index of the refraction medium  (Material B, n=5 / 4)

{n_i} is the refractive index of the incidence medium (Material A, n=4 / 3)

Hence,  

{\frac {4}{3}}\times {sin30.0^0}={\frac {5}{4}}\times{sin\theta_r}

Angle of refraction = sin^{-1}0.5333 = 32.2°

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Explanation:

i found the answer

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Hope you do well on the test and hope this helps!

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