A 0.750 kg ball is thrown vertically upward with an initial speed of 5.00 m/s. If the altitude at which the ball is defined to h
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Answer:
0.010 m
Explanation:
So the equation for a pendulum period is: where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:
Evaluate the multiplication in front
Divide both sides by 6.28
Square both sides
Multiply both sides by m/s^2 (the s^2 will cancel out)
Now now let's find the length when it's two seconds
Divide both sides by 6.28
Square both sides
Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)
So to find the difference you simply subtract
0.984 - 0.994 = 0.010 m