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2 years ago

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A 0.750 kg ball is thrown vertically upward with an initial speed of 5.00 m/s. If the altitude at which the ball is defined to h

ave zero gravitational potential energy is 1.00 m below its initial position, a simple calculation shows that its initial gravitational potential energy is 7.35 J. What is the ball's gravitational potential energy at 0.50 m above its initial position

1 answer:

Lelechka [254]2 years ago

4 0

Answer:

12.267367282991963672828w9

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Speed is v = d/t

Or speed is distance over time

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40min / 60min = 0.6667 or 2/3 --> Finding what proportion 40 minutes is to an hour or 60 minutes as we need the units of hours to match up

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d = (45)(0.667)

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3 years ago

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A charged object traveling 7 m in a uniform electric field of 5 N/C experiences a 4 J increase in Kinetic Energy.

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To solve this problem it is necessary to apply the principles of conservation of Energy in order to obtain the final work done.

The electric field in terms of the Force can be expressed as

$E = \frac{F}{q} \rightarrow F=Eq$

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q = Charge

Puesto que el trabajo realizado es equivalente al cambio en la energía cinetica entonces tenemos que

KE = W

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In the First Case,

$4 = (qE)d\\q = \frac{4}{Ed}\\q = \frac{4}{5*7}\\q = 0.1142C$

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2 years ago

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ASHA 777 [7]

Answer:

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Mamont248 [21]

Answer:

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3 years ago