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Luden [163]
3 years ago
7

A space station sounds an alert signal at time intervals of 1.00 h . Spaceships A and B pass the station, both moving at 0.400c0

relative to the station but in opposite directions.
Part A
How long is the time interval between signals according to an observer on A?
Part B
How long is the time interval between signals according to an observer on B?
Part C
At what speed must A move relative to the station in order to measure a time interval of 2.00 hbetween signals?
Physics
1 answer:
Ann [662]3 years ago
6 0

Answer:

(A). The the time interval between signals according to an observer on A is 1.09 h.

(B). The time interval between signals according to an observer on B is 1.09 h.

(C). The speed is 0.866c.

Explanation:

Given that,

Time interval = 1.00 h

Speed = 0.400 c

(A). We need to calculate the the time interval between signals according to an observer on A

Using formula of time

\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}

Put the value into the formula

\Delta t=\dfrac{1.00}{\sqrt{1-(\dfrac{0.400c}{c})^2}}

\Delta t=\dfrac{1.00}{\sqrt{1-(0.400)^2}}

\Delta t=1.09\ h

(B). We need to calculate the time interval between signals according to an observer on B

Using formula of time

\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}

Put the value into the formula

\Delta t=\dfrac{1.00}{\sqrt{1-(\dfrac{0.400c}{c})^2}}

\Delta t=\dfrac{1.00}{\sqrt{1-(0.400)^2}}

\Delta t=1.09\ h

(C). Here, time interval of 2.00 h between signals.

We need to calculate the speed

Using formula of speed

\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}

Put the value into the formula

2.00=\dfrac{1.00}{\sqrt{1-(\dfrac{v}{c})^2}}

\sqrt{1-(\dfrac{v}{c})^2}=\dfrac{1.00}{2.00}

1-(\dfrac{v}{c})^2=(\dfrac{1.00}{2.00})^2

(\dfrac{v}{c})^2=\dfrac{3}{4}

v=\dfrac{\sqrt{3}}{2}c

v=0.866c

Hence, (A). The the time interval between signals according to an observer on A is 1.09 h.

(B). The time interval between signals according to an observer on B is 1.09 h.

(C). The speed is 0.866c.

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