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3 years ago

Please help me with these calculating velocity questions im so stressed out

Physics

1 answer:

Darina [25.2K]3 years ago

3 0

Answer: -10m/s

Explanation:

Velocity is solved using the equation displacement over time. Part C shows a displacement or change in x of 30 and a change in time of 3 secs (7-10) so the equation would be 30m/3s= -10m/s it is negative because look at the slope. Its decreasing right? So that means the objects is slowing down which means it can't have a positive velocity

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A round loop of wire carries a current of 100 A, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a mag

Oliga [24]

Answer:

0.823 Nm

Explanation:

current, i = 100 A

radius, r = 10 cm

Angle between the normal and the magnetic field, θ = 30°

Magnetic field, B = 0.524 T

Torque is defined as the

$\tau = i \times A\ B\times sin\theta$

$\tau = 100 \times 3.14\times 0.1\times 0.1\ 0.524\times 0.5$

Torque = 0.823 Nm

Thus, the torque is 0.823 Nm.

7 0

4 years ago

A photon is absorbed by an electron that is in the n = 3 state of a hydrogen atom, causing the hydrogen atom to become ionized.

Wittaler [7]

Answer:

$\lambda=3.99*10^{-7}m$

Explanation:

According to the law of conservation of energy, the energy of the absorbed photon must be equal to the binding energy of the electron plus the energy of the released electron:

$E_p=E_b+E_r\\\frac{hc}{\lambda}=\frac{13.6eV}{n^2}+\frac{m_ev^2}{2}$

1 eV is equal to $1.6*10^{-19}J$ , so:

$13.6eV*\frac{1.6*10^{-19}J}{1eV}=2.18*10^{-18}J$

Solving for $\lambda$ and replacing the given values:

$\lambda=\frac{hc}{\frac{2.18*10^{-18}J}{n^2}+\frac{m_ev^2}{2}}\\\lambda=\frac{6.63*10^{-134}J\cdot s(3*10^8\frac{m}{s})}{\frac{2.18*10^{-18}J}{3^2}+\frac{(9.11*10^{-31}kg)(7.5*10^5\frac{m}{s})^2}{2}}\\\lambda=3.99*10^{-7}m$

4 0

3 years ago

The earth travels around the sun once a year in an approximately circular orbit whose radius is 1.50x10^11 m. From this data det

seraphim [82]

(a) Determine the circumference of the Earth through the equation,
C = 2πr
Substituting the known values,
C = 2π(1.50 x 10¹¹ m)
C = 9.424 x 10¹¹ m

Then, divide the answer by time which is given to a year which is equal to 31536000 s.
orbital speed = (9.424 x 10¹¹ m)/31536000 s

orbital speed = 29883.307 m/s

Hence, the orbital speed of the Earth is ~29883.307 m/s.

(b) The mass of the sun is ~1.9891 x 10³⁰ kg.

8 0

3 years ago

Convert 9.75 millimeters to centimeter

Butoxors [25]

Answer:

0.975cm

Explanation:

7 0

3 years ago

Read 2 more answers

At which temperature does the molecules of an object stop moving?

PilotLPTM [1.2K]

Answer:

at the melting point and boiling point

Explanation:

the heat abdorbed is used to break down the forces holding the particles together to allow it to change its state

7 0

3 years ago