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Natasha_Volkova [10]

4 years ago

14

What is the area of the circle with a radius of 12.77m

1 answer:

Arada [10]3 years ago

8 0

A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2

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Why does a rolling sphere slows down?

VLD [36.1K]

The sphere slow down due to friction force between the surface of the sphere and the surface on that the sphere is rolling . The friction force acting against the motion of the sphere. Thats why it is slowed down. In fact not only a sphere, anything can not slow down untill a force act against it's motion.

3 0

3 years ago

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A 11 g plastic ball is moving to the left at 29 m/s. How much work must be done on the ball to cause it to move to the right at

Rasek [7]

Answer:

4.25 J

Explanation:

Given that

mass of plastic ball = 11 g

Mass of plastic ball = 0.011 kg

velocity of ball = 29 m/s

We know that from work power energy theorem

$W_{all}=Change\ in\ kinetic\ energy\ of\ system$

We know that kinetic energy of moving mass given as

$KE=\dfrac{1}{2}mv^2$

Now by pitting the values

$KE=\dfrac{1}{2}mv^2$

$KE=\dfrac{1}{2}\times 0.011\times 29^2$

KE= 4.25 J

So the work done on the ball is 4.25 J

8 0

4 years ago

in baseball, a pitcher can accelerate 0.15kg ball from rest to 98 mi/hr in a distance of 1.7m. (a) What is the average force exe

Step2247 [10]

Answer:

F=84.68 N

Required force increases

Explanation:

By the equation

$v^{2}=u^{2} +2as\\ 98^{2}*1609.344^{2}/(60*60)^{2}=0+2*a*1.7\\a = 98^{2}*1609.344^{2}/((60*60)^{2}*2*1.7)\\a = 564.50m/s^{2} \\$

By newton's second law :

$F=ma\\F=0.15*564.50 \\F=84.68 N$

When the mass increased the force increases as the equation.

F=ma

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3 years ago

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What are physical properties?

Blizzard [7]

I'm pretty sure that the answer is C

4 0

4 years ago

A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center

blagie [28]

Explanation:

Given that,

Mass of the particle, m = 4 kg

Speed of the particle, v = 2.5 m/s

The radius of the circle, r = 2 m

We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :

$L=mvr$

Substitute all the values,

$L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s$

So, the angular momentum of the particle is 20 kg-m² s.

6 0

3 years ago