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IRISSAK [1]
3 years ago
13

Why are tigers and lions able to mate to produce cubs,but those cubs would not be able to go on to produce any off spring

Chemistry
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

Tigers and lions able to mate to produce cubs,but those cubs would not be able to go on to produce any off spring because their sex chromosomes do not match.

Explanation:

  • Tigers and lions mate to produce ligers and tilons but they do not produce viable sperms or egg.
  • In an organism there are two copies of chromosomes present in the somatic cells.
  • But in case of sex cells they receive each set from mother and father. which they duplicate and divide during formation of gametes via meiosis.
  • in such case if the sets are recieved from two different species then after pairing a mismatch will occur in the gene loci.For example, a eye colour gene may correspond to a paw length gene.
  • Thus the gametes when produced will not be viable.
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Glycogen ________. Glycogen ________. forms the regulatory molecules known as enzymes serves as a structural component of human
jasenka [17]

Answer:

Glycogen in an important storage polysaccharide found in animal tissues.

Explanation:

Full question:

Glycogen ________

A) forms the regulatory molecules known as enzymes

B) serves as a structural component of human cells

C) helps to protect vital organs from damage

D) is an important storage polysaccharide found in animal tissues

E) contains the genetic information found in cells

Glycogen is a complex polysaccharide of glucose founded in humans, animals, fungi and even bacteria. In humans, the glycogen is made and stored in liver cells. In the center on glycogen molecule, there is a single protein called Glycogenin. It is a center of a big flower made of glucose molecules (please refer to the scheme attached - Glycogenin is red and the blue lines are glucose chains). Glycogen is also stored in skeletal muscle, red and white blood cells, in glial brain cells and kidneys but in a smaller amounts. It can be found in the placenta in pregnant women where it serves as a nutrient storage for embryo. In an adult, the liver weighs 1,5 kg and glycogen weighs about 120g in such a liver. After a meal, the level of sugar is rising and the insulin is being secreted. Insulin is a tool by which sugar is being delivered to the cells, like a food delivery. During this period, glycogen is being synthesized in the liver out of glucose residues. When the meal is digested, the sugar level is back to normal. When more energy is needed, glycogen from the liver is broken down by glycogen phosphorylase and the new sugar is released into the bloodstream.

7 0
4 years ago
What is SO2 shape name?
muminat

Answer:Molecular Formula SO2

Hybridization Type sp2

Bond Angle 119o

Geometry V-Shaped or Bent

Explanation:

hope this helped <3

5 0
3 years ago
What particle decay is this? 210 83 Bi→210 84 Po ​
sesenic [268]

Answer:

Beta emission

Explanation:

In beta emission, a neutron is converted into a proton thereby emitting an electron and a neutrino. A neutrino is a particle that serves to balance the spins.

When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.

Hence, in beta emission, the daughter nucleus is found one pace to the right of the parent in the periodic table.

3 0
3 years ago
Balance the chemical equations.<br> 1FeCl3 + KOH → Fe(OH)3 + KC1
wariber [46]

Answer:

FeCl3 + 3KOH → Fe(OH)3 + 3KCl

Explanation:

3 0
3 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
4 years ago
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