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baherus [9]
3 years ago
5

True or False? SLOW moving water deposits sediment.

Chemistry
1 answer:
wolverine [178]3 years ago
7 0

no probs at all :)







5 pts

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Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11
Leona [35]

To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:

M1 V1 = M2 V2

So from the formula, we will know how much volume of the 1.50 M we actually need.

 

1.50 M * V1 = 0.100 M * 350 mL

V1 = 23.33 mL

 

So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:

350 mL – 23.33 mL = 326.67 mL water

 

 

Steps:

1. Take 23.33 mL of 1.50 M solution

<span>2. Add 326.67 mL of water to make 350 mL of 0.100 M solution</span>

7 0
3 years ago
What will happen to the pH of a solution when the [H+] is increased?
matrenka [14]

Answer:

decreases

Explanation:

the more conc of H ions increases the more it becomes acidic so the pH goes down

8 0
3 years ago
A phosphorus atom and a chlorine atom are likely to form a covalent bond because both elements:
Jobisdone [24]
A phosphorus atom and a chlorine atom are likely to form a covalent bond because both elements are nonmetals. 
4 0
3 years ago
Read 2 more answers
Which of the following is an example of a change of state?
lord [1]

Answer:

Option B

Explanation:

  • For Option A the state is not changing but just has different look now.
  • For Option B the state is changing from gas to liquid drops due to cold glass
  • For Option C it hasn't changed state as both corn and flower is solid
  • For Option D paper and ash are both solids

Therefore our answer must be Option B

6 0
2 years ago
9.86 x 10²⁸ O-atoms require what volume (L) N₂O₂ at STP?
jolli1 [7]
First, we use avogadro's number to convert atoms into moles. Then, relate the number of moles from elemental to the compound. Lastly, we use conditions at STP to calculate the volume. We do as follows:

<span>9.86 x 10²⁸ O-atoms ( 1 mol / 6.022x10^23 atoms O) ( 1 mol N2O2 / 2 mol O ) ( 22.4 L / 1 mol ) = 1833809.37 L needed</span>
8 0
3 years ago
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