For this question, we can use relations for pH and pOH. We calculate as follows:
pOH = -log [OH-]
pOH = -log [<span>1.83x10^-7 M]
pOH = 6.74
pH + pOH = 14
pH = 14 - 6.74
pH = 7.26
pH = -log [H3O+]
7.26 = -log[H3O+]
[H3O+] = 5.46 x 10^-8 M
Hope this answers the question. Have a nice day.</span>
Density = mass / volume
Density = 22.8/14.7
Density = 1.6
Electron affinity is the change in energy of an atom with a neutral charge when an electron is added to form an anion. A more negative electron affinity corresponds to a greater attraction for an electron. Electron affinity become less negative down a group and from left to right in the periodic table.
Answer:
The answer is A
Explanation:
Let's break this down. . .
-The lower the pH, the more acidic.
-So, the pH of 2 is more acidic than 3.
-Then, it's pretty obvious that the concentration with more acidic substance will be greater or higher than the other substance.
- As a result, the concentration of pH 2 will be greater or higher than the concentration of pH 3.
If you want the "mathematical" form then here:
Concentration
A pH of 2 would be 10 to the -2; 10^-2 which will equal 0.01
A pH of 3 would be 10 to the -3; 10^-3 which will equal 0.001
Which one is greater than the other?
A substance with a pH of 2 has a 10 times higher concentration of H* than a substance with pH of 3.
Answer:
Trend in ionic character of bonds: Cs-F > Si-C > Br-Cl > Cl-Cl
(most) (least)
Explanation:
We know that, percentage ionic character of a bond is proportional to electronegativity difference between two constituting atoms.
Atom Electronegativity
Cs 0.7
F 4.0
Cl 3.0
Br 2.8
Si 1.8
C 2.5
Bond Electronegativity difference
Cs-F 3.3
Cl-Cl 0.0
Br-Cl 0.2
Si-C 0.7
So trend in ionic character of bonds:
Cs-F > Si-C > Br-Cl > Cl-Cl
(most) (least)