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3 years ago

What is the approximate distance from the sun to the astroid belt?

Physics

1 answer:

IrinaVladis [17]3 years ago

6 0

Answer:

The asteroid belt lies between 2.2 and 3.2 astronomical units (AU) from our sun. ( i looked this up because nobody of the top of their head knows this)

Explanation:

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An object is realsed From rest . how far does it fall during the second second of fall?

Savatey [412]

Answer:

14.715 m

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards, take downwards as positive

First second:

v = u + at

v = 9.81 m/s

Second second:

s = ut + (1/2)at^2

s = 9.81(1) + (1/2)(9.81)(1)^2

s = 14.715 m

6 0

3 years ago

You place a box weighing 253.1 N on an inclined plane that makes a 39.7◦ angle with the horizontal.

Masja [62]

Answer:

Explanation:

The weight of the box is

W = 253.1N

Weight is on an incline plane

θ = 39.7°

The weight of an object is always acting downward

So, the weight makes an angle of 39.7° with the vertical component

Then, it's horizontal component is

Wx = W•Sinθ

Wx = 253.1 × Sin 39.7°

Wx = 161.67 N

The horizontal component of the weight is 161.67N

This is the force acting down the plane.

Check attachment

7 0

4 years ago

CALCULATE THE DECELERATION OF A RUNNER

AlexFokin [52]

Answer:

$a = \frac{ {v}^{2} - {u}^{2} }{2s} \\ or \\ a = \frac{v - u}{t} \\ say \: a = - 10m. {s}^{ - 2} \\ \therefore \: deceleration = - 10m. {s}^{ - 2}$

5 0

3 years ago

An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 18

Salsk061 [2.6K]

Explanation:

Given that,

Potential difference, V = 412 V

Magnitude of magnetic field, B = 188 mT

(a) The potential energy of electron is balanced by its kinetic energy as :

$eV=\dfrac{1}{2}mv^2$

v is speed of the electron

$v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s$

(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :

$r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m$

Hence, this is the required solution.

7 0

3 years ago

Which of the following activities could lead to injuries?

Ipatiy [6.2K]

Answer:

Fighting

Explanation:

Fighting with someone like punch for punch can make the person bleed which an injury to the guy who you fought with and you can be arrested if the parents file a complain at the police station

6 0

3 years ago

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What is the approximate distance from the sun to the astroid belt￼?

What is the approximate distance from the sun to the astroid belt?