A hard rubber ball is thrown level to the ground at a speed of 25 m/s and an initial height of 2.0 meters. Which best describes
1 answer:
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Time required : 25.876 s
<h3>Further explanation</h3>Given
A car weight = 25000 N
Brake force = 628 N
vo= 6.5 m/s
vt = 0(stop)
Required
time to stop
Solution
W = m . g
25000 = m.10
m=2500 kg
Newton's second law
F = m . a
628 = 2500 . a
vt=vo-at(deceleration a=-)
0=6.5-0.2512.t
0.2512.t=6.5
t=25.876 s
Answer:
twice the original speed
Explanation:
the centripetal force is the force of an object moving in a circle of turning and it is given by the expression
where f = force of the object
m = mass
v = velocity
r = radius of the circle
first we need to know what the orignal speed will be then we can tell what will happen if the radius of the circle is changed to 4R.
from the expression for the centripetal force, we need to make the velocity subject of the formula
now, if the radius is changed to 4R
in the expression for v above i will need to just insert 4R in place of r
the square root of 4 is 2,
therefore
we can see that this is just twice of what the original speed was.