Answer:
b) the result we got can be termed approximation because we are neglecting the shear stress acting on the two ends of the cylinder. Here we have considered only the share stress acting on the curved surface area only.
Explanation:
check attachment for solution to A
Answer:
S = 4.08 m/s
Explanation:
given,
initial speed, v = 20.5 m/s
angle made with horizontal, θ = 45°
Distance of player = 55 m
Average speed of the player to catch the ball = ?
vertical velocity of the ball =
v_y = v sin θ = 20.5 x sin 45° = 14.5 m/s
horizontal velocity of the ball
v_x = v cos θ = 20.5 x cos 45° = 14.5 m/s
time taken by the ball to reach at the highest point
v = u + g t
v = V_y - g t
0 = 14.5 - 9.8 x t
t = 1.48 s
total time of flight = 2 t = 1.48 x 2 = 2.96 s
Horizontal distance travel by the ball
s = vₓ x t
s = 14.5 x 2.96
s = 42.96 m
distance player has to run
D = 55 - 42.96 = 12.08 m
Average speed of the player
S = 4.08 m/s
Speed of the player is equal to 4.08 m/s