the electrostatic force between two objects is 40N. if the charge of one object is cut in half, and the distance is doubled, wha
t is the new force?
1 answer:
Answer:
F1 = K Q1 Q2 / R1^2
F2 = K Q1 / 2 * Q2 / (2 R1)^2
F2 / F1 = 1/2 / 4 = 1/8
The new force is 5N (1/2 due to charge and 1/4 due to distance)
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