A small rubber wheel drives the rotation of a larger pottery wheel by running along its edge. The small wheel radius is 1.2 cm,
1 answer:
Answer:
α₂= 0.1 rad/s²
t= 62.8 s
Explanation:
Given that
For small wheel
r₁= 1.2 cm
α₁ = 3 rad/s²
For large wheel
r₂= 36 cm
Angular acceleration = α₂ rad/s²
The tangential acceleration for the both wheel will be same
a = α₁ r₁=α₂ r₂
Now by putting the values in the above equation
α₁ r₁=α₂ r₂
3 x 1.2 = 36 x α₂
α₂= 0.1 rad/s²
Given that
N = 60 rpm
Angular speed in rad/s ω
ω = 6.28 rad/s
Time taken is t
ω = α₂ t
6.28 = 0.1 t
t= 62.8 s
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(3) mass-energy must be conserved
Explanation:
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Now in case of Pair production the gamma photons convert its whole energy into mass by the law of Einstein's mass energy equivalence relation.
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