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bulgar [2K]
2 years ago
15

A piece of aluminum requires 4,000 J of energy to change

Physics
1 answer:
photoshop1234 [79]2 years ago
8 0

Answer:

Mass, m = 105.58 g

Explanation:

We have,

Heat required in aluminium to change the temperature from 68°C to 110°C. It is required to find the mass of aluminium.

Concept used : Specific heat capacity

Solution,

The heat required to raise the temperature is given by :

Q=mc\Delta T

c is specific heat capacity, for Aluminium, c = 0.902 J/g-°C

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{4000\ J}{0.902\ J/g^{\circ} C\times (110-68)^{\circ} C}}\\\\m=105.58\ g

So, the mass of aluminium is 105.58 grams.

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Suppose you are observing the interference pattern formed by a Michelson interferometer in a laboratory and a joking colleague h
Troyanec [42]

Answer:

Explanation:

In Michelson interferometer , two light waves from different directions are made to overlap so that fringes are formed on the screen due to interference . In it,  two monochromatic and coherent light are made to overlap which have some path difference or phase difference. They form dark and bright fringes .

Now when a match stick is lit in the path of a wave , the fringes will disappear  and an general illumination will be observed on the screen as the light from the lit match stick will not be coherent . Incoherent light can not form stable fringes.

7 0
3 years ago
Identify the smallest unit of an element
marysya [2.9K]

atom ................................................... sorry for the periods

3 0
3 years ago
Read 2 more answers
Two particles, each with charge Q, and a third charge q, are placed at the vertices of an equilateral triangle as shown. The tot
Gelneren [198K]

Answer:

<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>

Explanation:

The image is shown below.

The force on the particle with charge q due to each charge Q = \frac{kQq}{r^{2} }

we designate this force as N

Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.

Resolving the forces on the particle, we have

for the x-component

N_{x} = N cosine 60° + (-N cosine 60°) = 0

for the y-component

N_{y} = -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N

The above indicates that there is no resultant force in the x-axis, since it is equal to zero (N_{x} = 0).

The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.

<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>

5 0
3 years ago
What do all types of electromagnetic radiation have in common?
Andrew [12]
<span>They are emitted by the unstable nuclei of certain atoms.
 That's all I could find out; Sorry I couldn't be more of an help.</span>
5 0
2 years ago
What did you notice about the angle of incidence and the angle of reflection?
Readme [11.4K]

Answer:

They are equal

Explanation:

angle of incidence = angle of reflection

6 0
2 years ago
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