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bulgar [2K]
3 years ago
15

A piece of aluminum requires 4,000 J of energy to change

Physics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

Mass, m = 105.58 g

Explanation:

We have,

Heat required in aluminium to change the temperature from 68°C to 110°C. It is required to find the mass of aluminium.

Concept used : Specific heat capacity

Solution,

The heat required to raise the temperature is given by :

Q=mc\Delta T

c is specific heat capacity, for Aluminium, c = 0.902 J/g-°C

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{4000\ J}{0.902\ J/g^{\circ} C\times (110-68)^{\circ} C}}\\\\m=105.58\ g

So, the mass of aluminium is 105.58 grams.

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Ok plz answer and tell me how to do it
kirza4 [7]
Answer: 25N

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4 0
3 years ago
A fluid flows through a pipe whose cross-sectional area changes from 2.00 m2 to 0.50 m2 . If the fluid’s speed in the wide part
borishaifa [10]

Answer:

v₂ = 7/ (0.5)= 14 m/s

Explanation:

Flow rate of the fluid

Flow rate is the amount of fluid that circulates through a section of the pipeline (pipe, pipeline, river, canal, ...) per unit of time.

The formula for calculated the flow rate is:

Q= v*A Formula (1)

Where :

Q is the Flow rate (m³/s)

A is the cross sectional area of a section of the pipe (m²)

v is the speed of the fluid in that section (m/s)

Equation of continuity

The volume flow rate Q for an incompressible fluid at any point along a pipe is the same as the volume flow rate at any other point along a pipe:

Q₁= Q₂

Data

A₁ = 2m² : cross sectional area 1

v₁ = 3.5 m/s : fluid speed through A₁

A₂ = 0.5 m² : cross sectional area 2

Calculation of the fluid speed through A₂

We aply the equation of continuity:

Q₁= Q₂

We aply the equation of Formula (1):

v₁*A₁= v₂*A₂

We replace data

(3.5)*(2)= v₂*(0.5)

7 = v₂*(0.5)

v₂ = 7/ (0.5)

v₂ =  14 m/s

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vampirchik [111]

Answer:

Explanation:

Examples are;

Ultraviolet light from sun.

Heat from a stove burner.

X-ray from an x-ray machine.

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Sound waves from your stereo.

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ultraviolet light from a black light.

Gamma radiations from a supernova.

AND MANY MORE.

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