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bulgar [2K]
3 years ago
15

A piece of aluminum requires 4,000 J of energy to change

Physics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

Mass, m = 105.58 g

Explanation:

We have,

Heat required in aluminium to change the temperature from 68°C to 110°C. It is required to find the mass of aluminium.

Concept used : Specific heat capacity

Solution,

The heat required to raise the temperature is given by :

Q=mc\Delta T

c is specific heat capacity, for Aluminium, c = 0.902 J/g-°C

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{4000\ J}{0.902\ J/g^{\circ} C\times (110-68)^{\circ} C}}\\\\m=105.58\ g

So, the mass of aluminium is 105.58 grams.

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Which of the following would most likely cause a decrease in the quality supplied
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AWhich of the following would most likely cause a decrease in the quantity supplied? A decrease in price.

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3 years ago
In a certain region of space, the electric potential is V(x,y,z)=Axy-Bx^2+Cy , where A,B , and C are positive constants.a) Calcu
laiz [17]

Answer:

a)  Eₓ = - A y + 2B x , b)  Ey = -Ax –C , c) Ez = 0 , d) The correct answer is 3

Explanation:

The electric field and the electric power are related

                    E = - dV / ds

a) Let's find the electric field on the x axis

                  Eₓ = - dV / dx

                  dV / dx = A y - B 2x

                  Eₓ = - A y + 2B x

b) calculate the electric field on the y-axis

                Ey = - dV / dy

                dV / dy = A x + C

                Ey = -Ax –C

c) the electric field on the z axis

              dv / dz = 0

              Ez = 0

.d) at which point the electric field is zero

Since the electric field is a vector quantity all components must be zero

X axis

              0 = = - A y + 2B x

              y = 2B / A x

Axis y

             0 = -Ax –C

              .x = -C / A

We substitute this value in the previous equation

             .y = 2B / A (-C / A)

             .y = 2 B C / A2

The correct answer is 3

6 0
4 years ago
How much thermal energy is required to raise the temperature of 5 kg of water 50℃? The specific heat of water is 4168 J/kg*C.
sasho [114]

Answer/solution:

Given :

Mass =5kg

T 1 =20 C,T 2  =100 ∘C

ΔT=100−20=80 ∘C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

3 0
2 years ago
What is a oxidation number
Scilla [17]
Oxidation number is the charge.
6 0
3 years ago
Read 2 more answers
Samantha is refinishing her rusty wheelbarrow. She moves her sandpaper back and forth 45 times over a rusty area, each time movi
Leviafan [203]

Answer:

W = 12.96 J

Explanation:

The force acting in the direction of motion of the sand paper is the frictional force. So, we first calculate the frictional force:

F = μR

where,

F = Friction Force = ?

μ = 0.92

R = Normal Force = 2.6 N

Therefore,

F = (0.92)(2.6 N)

F = 2.4 N

Now, the displacement is given as:

d = (0.12 m)(45)

d = 5.4 m

So, the work done will be:

W = F d

W = (2.4 N)(5.4 m)

<u>W = 12.96 J</u>

5 0
3 years ago
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