The potential at location A is 382 V. A positively charged particle is released there from rest and arrives at location B with a
1 answer:
Answer: 247.67 V
Explanation:
Given
Potential At A
Potential at
when particle starts from A it reaches with velocity at Point while when it starts from C it reaches at point B with velocity
Suppose m is the mass of Particle
Change in Kinetic Energy of particle moving under the Potential From A to B
Change in Kinetic Energy of particle moving under the Potential From C to B
Divide 1 and 2 we get
on solving we get
You might be interested in
We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
where
Now we find the moment of inertia by integrating from
to 
The moment of inertia is
(from (-a/2) to
(a/2))
where
Now we find the moment of inertia by integrating from
The moment of inertia is
Answer:
19 m/s
Explanation:
The complete question requires the final speed to be calculated.
Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.
For this question, first the unknown acceleration must be calculated and used to determine the final velocity
Step 1: Calculate the acceleration
Step 2: Calculate the velocity using the acceleration calculated above