Answer:
500 J.
Explanation:
Work done = force * distance
= 25 * 20
= 500 Joules.
PART A)
momentum of Bill's car
mass = 900 kg
speed = 3.5 m/s towards west
so momentum of this car given as
Similarly momentum of Tanya's car
mass = 1100 kg
speed = 2 m/s towards East
so momentum will be
Total momentum of both cars will be
Towards west
PART B)
Since there is no external force on the system of two cars
So here total momentum of both cars will remains conserved
So final momentum of two cars will be same as initial momentum
towards west
Part C)
final momentum of Bills car
Towards East
now we have
towards west
Answer:
option (b)
Explanation:
Let both teh springs are extended by y.
For first spring
m1 x g = k1 x y
where, m1 is the mass of first ball and k1 be the spring constant of first spring
.... (1)
For second spring
m2 x g = k2 x y
where, m2 is the mass of second ball and k2 be the spring constant of second spring
.... (2)
The frequency of the body is given by
So, from equation (1) and equation (2), the ratio of k is to m is same, so the frequency of both the balls is same.
The answer is 5. To find the advantage you just divide 20 by 4.