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tia_tia [17]
3 years ago
5

A projectile of mass 0.2 kg and an initial velocity of 50 m/s collides with the end of a blade attached to a turbine. The rotati

onal inertia of the turbine is 12.5 kg⋅m2 . Assume the loss of energy of the projectile in the collision is completely transferred to the blades, causing them to spin. If the final rebound velocity of the projectile after hitting a turbine blade is −25 m/s , which of the following is most nearly the rotational velocity of the turbine after the collision?
Physics
1 answer:
fgiga [73]3 years ago
8 0

Answer:

5.5 rad/sec

Explanation:

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harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

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n_{air} = Refraction index of air

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I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

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Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
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sergejj [24]

Answer:

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Explanation:

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Explanation:

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Answer:

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