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Elanso [62]
2 years ago
11

If the radius of a coinis 20cm, find itssurface area -​

Physics
1 answer:
meriva2 years ago
8 0

Answer:

800\picm²

Explanation:

Given parameters:

radius of the coin  = 20cm

Unknown:

Surface area of the coin  = ?

Solution:

A coin is made up of two faces;

  Surface area  = 2(πr²)

Insert the parameters and solve;

     Surface area = 2(\pi  x 20^{2})

    Surface area = 800\picm²

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Answer:

it wont be because the hand brake would be on

4 0
3 years ago
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Explain what kind of heat transfer occurs when you burn yourself on a hot car seat in the summer.
liubo4ka [24]
Conduction is a mode of transfer of heat there
6 0
3 years ago
During an isothermal process, 10 j of heat is removed from an ideal gas. What is the work done by the gas in the process?
Black_prince [1.1K]

The work done in the isothermal process is 10 joule.

We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.

ΔU = 0

Hence,

ΔU = Q - W

0 = Q - W

Q = W

It means that the heat transferred is the same as the work done.

From the question above, we know that the heat transferred is 10 joule. Thus, the work done in the isothermal process is 10 joule.

Find more on isothermal at: brainly.com/question/17097259

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8 0
1 year ago
A tube is sealed at both ends and contains a 0.0100-m long portion of liquid. The length of the tube is large compared to 0.0100
Ahat [919]

Answer:

31.321 rad/s

Explanation:

L = Tube length

A = Area of tube

\rho = Density of fluid

v = Fluid velocity

m = Mass = \rho Al

Centripetal force is given by

F=\dfrac{mv^2}{L}\\ F=\dfrac{m(\omega L)^2}{L}\\ F=m\omega^2\\ F= 0.01A\rho\omega^2L

Pressure is given by

P=\dfrac{F}{A}=\rho gL\\\Rightarrow \dfrac{0.01A\rho\omega^2L}{A}=\rho gL\\\Rightarrow 0.01\omega^2=g\\\Rightarrow \omega^2=\dfrac{g}{0.01}\\\Rightarrow \omega=\sqrt{\dfrac{g}{0.01}}\\\Rightarrow \omega=\sqrt{\dfrac{9.81}{0.01}}\\\Rightarrow \omega=31.321\ rad/s

The angular speed of the tube is 31.321 rad/s

5 0
3 years ago
A force of 720 Newton stretches a spring 4 meters. A mass of 45 Kilograms is attached to the spring and is initially released fr
poizon [28]

Answer:

x(t) = -3sin2t

Explanation:

Given that

Spring force of, W = 720 N

Extension of the spring, s = 4 m

Attached mass to the spring, m = 45 kg

Velocity of, v = 6 m/s

The proper calculation is attached via the image below.

Final solution is x(t) = -3.sin2t

5 0
3 years ago
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