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3 years ago

Calculate volume of 16g of sulfur Dioxide,SO2 at Stp

Chemistry

1 answer:

Anni [7]3 years ago

8 0

Answer:

5.6L

Explanation:

Given parameters:

Mass of sulfur dioxide = 16g

Unknown:

Volume of at STP = ?

Solution:

The volume of gas at STP;

Number of moles = $\frac{volume of gas}{22.4}$

The volume of the gas = number of moles x 22.4

Number of moles = $\frac{mass}{molar mass}$

Molar mass of SO₂ = 32 + 2(16) = 64g/mol

Number of moles = $\frac{16}{64}$ = 0.25mole

Volume of the gas = number of moles x 22.4

Volume of the gas = 0.25 x 22.4 = 5.6L

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Write the full electron configuration of the Period 2 element with the following successive IEs (in kJ/mol):

Julli [10]

Answer:

Boron (B) is the element whose IE matches with our data.

Electronic Configuration of boron: $1s^22s^22p^1$

Explanation:

Ionization Energy (IE):

It is the minimum amount of energy which is required to remove the lose electron. If the electron is closer to the nucleus then greater amount of energy is required to remove the electron.

If we look from left to right in a period, ionization energy increases due stability of valance shell.

From the data given to us:

IE₁ = 801

IE₂ = 2427

IE₃ = 3659

IE₄ = 25,022

IE₅ = 32,822

Boron (B) is the element whose IE matches with our data.

Electronic Configuration of boron: $1s^22s^22p^1$

Boron has 5 electrons (3 in valance shell) that's why it has 5 Ionization Energies.

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3 years ago

How much heat is required to convert 90. g of ice at -4.0 C to water vapor (steam) at 110 C

lakkis [162]

Answer: How much heat is required to convert 29 g of ice at -4.0 ˚C to water vapor at 105 ˚C (report your answer to three significant figures)? Answer all five parts, showing your detailed calculations: i) Heat to warm ice from -4.0 to 0 oC: ii) Heat to convert ice to liquid: iii) Heat to warm liquid to boiling: iv) Heat to convert liquid to gas

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Explanation:

6 0

2 years ago

how many grams of fertilizer , for potassium sulfate are there in 42.3 mole of potassium sulfate? step by step

Over [174]

Answer:

The mass of 42.3 moles of potassium sulfate is 7,371.1557 grams

Explanation:

Potassium sulfate K₂SO₄ which is also known as sulphate of potash is a water soluble common component of fertilizer

The molar mass of potassium sulfate, M = 174.259 g/mol

The given number of moles of potassium sulfate, n = 42.3 moles

The mass, 'm', of a given number of moles of potassium sulfate, 'n', is given as follows;

m = n × M

Therefore, we have;

The mass, 'm', of 42.3 moles of potassium sulfate is found by plugging in the values for 'M', and 'n', in the above equation as follows;

m = 42.3 moles × 174.259 g/mol = 7,371.1557 grams

The mass of 42.3 moles of potassium sulfate, m = 7,371.1557 grams.

4 0

3 years ago

Which statement explains why carbon dioxide (CO2) is a gas at room temperature? A. There are constant interactions between the C

Nezavi [6.7K]

Answer:

B) There are weak interactions between the CO2 molecules.

Explanation:

Carbon dioxide is composed of one carbon atom that is structured between two atoms of oxygen, they are bonded with double bond and the CO2 is symmetrical because of the arrangement of the bond between them.It is less electronegative than Oxgen, this gives Oxgen the ability to attract the electron to themselves, and there is no intermolecular existing within carbon dioxide other bands waal forces.Compounds that are gases under the condition of room temperatures, and pressure usually have have small molecules. and their molecules is usually have van der Waals forces acting between them and theses forces are weak.This allows carbon dioxide molecules to be able to move freely as a gas.

6 0

4 years ago

At what temperature would a 1.30 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86

Setler [38]

Answer:

-4.59°C

Explanation:

Let's see the formula for freezing point depression.

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Freezing constant. For water if 1.86°C/m

m = molality (moles of solute in 1kg of solvent)

i = Van't Hoff factor.

0°C - Freezing T° of solution = 1.86°C /m . 1.30m . 1.9

Freezing T° of solution = - (1.86°C /m . 1.30m . 1.9)

Freezing T° of solution = - (1.86°C/m . 1.30m . 1.9) → -4.59°C

NaCl → Na⁺ + Cl⁻

4 0

3 years ago

Calculate volume of 16g of sulfur Dioxide,SO2 at Stp​

Calculate volume of 16g of sulfur Dioxide,SO2 at Stp