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dybincka [34]
3 years ago
12

Some students have said that a buffer is like a proton (H ) sponge. Evaluate this statement and explain both how a buffer is lik

e a sponge and how it is not like a sponge. For your explanation, include chemical equations, data, and create and explain molecular-level drawings. (Question is taken from Orgill and Sutherland, 2008.) (Saloni)
Chemistry
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

i)  Buffer absorbs  H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH

ii) absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.

Explanation:

<u>i) Buffer like a proton ( H ) sponge </u>

Buffer absorbs  H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH

The pH of a Buffer follows the Henderson-Hasselbach model

pH = pKa + Log ([A-]/[HA])

when base is added

HA + OH^-   -------> A- + H2O

when acid is added

A^- + H^+   ---------> HA

<u>ii) Buffer not like a proton ( H ) sponge</u>

absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.

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A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest the man and puck moved together after the collision.
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Answer: The final velocity of both man and hokey puck will be 0.056 m/s.

Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.

This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.

Sum of Initial momentum of two objects = Sum of Final momentum of the two objects

Mathematically,

m_1u_1+m_2u_2=m_1v_1+m_2v_2     ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of the first object.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of the second object.

Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

m_1=80.00kg\\m_2=0.16kg\\u_1=0m/s\\u_2=28m/s\\v_1=v_2=V=?m/s

Putting values in equation 1, we get:

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The final velocity of man and hockey puck is 0.056 m/s.

6 0
3 years ago
Read 2 more answers
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