Question

find the equation for the line passing through the point (-2,4) and parallel to the line whose equation is y=3x+11

Answer 1

Answer: y = 3x+10

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Explanation:

The line y = 3x+11 is in slope intercept form y = mx+b where m = 3 is the slope. Anything parallel to this line will also have a slope of 3. Let's plug in m = 3 and (x,y) = (-2,4) which is the point this parallel line goes through.

y = mx+b

y = 3x+b ... replace m with 3

4 = 3(-2)+b ... replace x with -2; replace y with 4

4 = -6+b

4+6 = -6+b+6 ... add 6 to both sides

10 = b

b = 10

Since m = 3 and  b = 10, this means that y = mx+b turns into y = 3x+10