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vfiekz [6]
3 years ago
10

PLEASE HELP ME WITH PROOFS . DONT ANSWER IF YOU DONT KNOW. BRAINLY FOR CORRECT ANSWER

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0

Step-by-step explanation:

Does this help?

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What will the last payment be to pay off a $1,250 computer plus 8% sales tax with monthly payments of $120?
GrogVix [38]
Convert 8% too decimal form = 8/100 = .08
1250 * .08 = 100
1250 + 100 = 1350
To find out how many payments of 120 can be made :
120x = 1350
divide both sides by 120
x = 11.25 payments of $120
since .25 is a fraction calculate the actual $ amount by mult. 120 * .25 = $30
The last payment is $30

8 0
3 years ago
The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the
kicyunya [14]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
4(3x-2)+6x(2-1) simplified
FrozenT [24]

Answer:

The answer is 18x - 8.

Step-by-step explanation: Trust me, an know a lot about math.

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