The volume of the gas once it reaches the surface of water is 2 liters.
The volume of the air in balloon at depth of 100ft (30m) is 500ml.
The pressure at this point is 4 atm.
Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.
The pressure at the surface of water is 1 atms.
As we know, from the ideal gas equation,
PV = nRT
Where,
P is the Pressure of gas,
V is the volume of the gas,
n is the number of moles,
R is the gas constant whose value is 0.082057 L atm mol-1 K-1,
T is the temperature.
Assuming that the temperature is constant,
We know,
PV = nRT
All quantities on the right side are constants,
So, we can write,
P₁V₁ = P₂V₂
Putting all the the values,
4(0.5) = 1V₂
V₂ = 2 Liters.
The volume of the air at the surface is 2 liters.
1 liter = 0.001 m
Hence,
2 liters = 0.002 m³
So the volume of air at the surface is 0.002m³.
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