Answer:
31 miles
Step-by-step explanation:
If you multiply 0.62 by 50 you will get 31.
Please keep in mind that I am human and make mistakes. This answer could be wrong but this is my opinion on what the answer is.
average rate of change of work from max. height unitil it reaches the ground 4 ≥ t .
<h3>WHAT IS AVERAGE RATE ? </h3>
The average rate at which one quantity changes in relation to another's change is referred to as the average rate of change function. A method that determines the amount of change in one item divided by the corresponding amount of change in another is known as an average rate of change function.
<h3>CALCULATION</h3>
h(t)=-16t^2+144t
= 16t [ 4 - t ]
4 - t ≥ t
domain is (0,4)
t is the time , time must be positive so domain starts from zero .
learn more about average rate of change here :
brainly.com/question/23715190
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The x-values that will make the output values of the floor and ceiling functions equal are;
Option A: -8
Option D: 0
The complete question is;
At which x-values are the output values of the floor function g(x) = ⌊x⌋ and the ceiling function h(x) = ⌈x⌉ equal? Check all that apply.
A) –8
B) –5.2
C) –1.7
D) 0
E) 2.4
When it comes to floor functions and ceiling functions, they are always equal to each other when the x value is an integer.
Now, looking at the giving options the only integers we have are -8 and 0.
Thus, the only values in the options that would make the output values of the floor function and ceiling function equal are -8 and 0.
Read more on floor function and ceiling function at; brainly.com/question/7321190
Graph it on graph paper then connect the dots then you can measure each side by the amount of boxes and then you take base × height ÷2
Answer:
Step-by-step explanation:
Depends upon what you're looking for! If you want the area under the standard normal curve to the left of z = -3.49, here's one way to do it on a TI 83 calculator:
normcdf(-100, -3.49). Because the z-value -3.49 is more than 3 standard deviations below the mean, the area to the left of z = -3.49 resembles 0.002. Try this on your calculator: normcdf(-100, -3.49)