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Nataly_w [17]
3 years ago
15

What is the initial vertical velocity of the ball?

Physics
1 answer:
Dmitry [639]3 years ago
6 0
I think that it is B hope this helps
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A plane flies from basecamp the Lake A, 280 km away in a direction of 20° north of
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A beam of light strikes a mirror reflects off at the angle in which it hit the mirror. which term does the diagram below illustr
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B.) reflection

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What nonliving materials are important to living things?
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How much time would it take for an object to fall 4.7 meters
alukav5142 [94]

Answer:

t = 0.97 s

Explanation:

Given that,

height, h = 4.7 m

We need to find the time taken by the object to fall 4.7 m.

Let it is t. Using second equation of kinematics to solve it such that,

h=ut+\dfrac{1}{2}gt^2

u is initial velocity, u = 0

So,

h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}}\\\\t=\sqrt{\dfrac{2\times 4.7}{9.8}}\\\\t=0.97\ s

So, the required time is equal to 0.97 seconds.

4 0
3 years ago
in what distance can a 1500kg automobile be stopped if the brake is applied when the speed is 20m/s and the coefficient of slidi
natali 33 [55]

1) The braking force is provided by the frictional force, which is given by:

F_f=\mu m g

where

\mu=0.7 is the coefficient of friction

m=1500 kg is the mass of the car

g=9.81 m/s^2 is the gravitational acceleration


Substituting numbers into the equation, we find

F_f= (0.7)(1500 kg)(9.81 m/s^2)=10301 N


2) The work done by the frictional force to stop the car is equal to the product between the force and the distance d:

W=-F_fd (1)

where we put a negative sign because the force is in the opposite direction of the motion of the car.


3) For the work-energy theorem, the work done by the frictional force is equal to the variation of kinetic energy of the car:

\Delta K=K_f -K_i =W (2)

The final kinetic energy is zero, so the variation of kinetic energy is just equal to the initial kinetic energy of the car:

\Delta K=-K_i=-\frac{1}{2}mv^2=-\frac{1}{2}(1500 kg)(20 m/s)^2=-300000 J


4) By equalizing eq. (1) and (2), we find the distance, d:

-K_i = -Fd

d=\frac{K_i}{F}=\frac{300000 J}{10301 N}=29.1 m

8 0
3 years ago
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