I need help on 2/3 please asap thx ♥️
1 answer:
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Answer
given,
initial speed,u = 0 m/s
final speed,v = 24.8 m/s
time, t= 5.9 s
a) acceleration,
a = 4.20 m/s²
b) distance to travel in that time
using equation of motion
v² = u² + 2 as
24.8² = 0² + 2 x 4.20 x s
8.4 s = 615.04
s = 73.22 m
the motorcycle will travel 73.22 m
Answer:
Δx = 39.1 m
Explanation:
- Assuming that deceleration keeps constant during the braking process, we can use one of the kinematics equations, as follows:
where vf is the final velocity (0 in our case), v₀ is the initial velocity
(25 m/s), a is the acceleration (-8.0 m/s²), and Δx is the distance
traveled since the brakes are applied.
- Solving (1) for Δx, we have: