A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is
1 answer:
Answer:
0.2
Explanation:
Horizontal force=100N
Weight of crate=500 N
We have to find the coefficient of kinetic friction.
Normal ,N=Weight=500N
Horizontal force,
Where =Horizontal force
N=Normal force
=Coefficient of kinetic friction
Substitute the values in the formula
Hence, the coefficient of kinetic friction =0.2
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Answer:
Explanation:
Given that
The electric fields of strengths E = 187,500 V/m and
and The magnetic fields of strengths B = 0.1250 T
The diameter d is 25.05 cm which is converted to 0.2505m
The radius is (d/2)
= 0.2505m / 2 = 0.12525m
The given formula to find the magnetic force is
The given formula to find the electric force is
The velocity of electric field and magnetic field is said to be perpendicular
Electric field is equal to magnectic field
Equate equation (i) and equation (ii)
It is said that the particles moves in semi circle, so we are going to consider using centripetal force
magnectic field is equal to centripetal force
Lets equate equation (i) and (iii)
Therefore, the particle's charge-to-mass ratio is
b)
To identify the particle
Then 1/ 958.1 × 10⁵ C/kg
The charge to mass ratio is very close to that of a proton, which is about 1*10^8 C/kg
Therefore the particle is proton.
Answer:
E = 1.655 x 10⁷ N/C towards the filament
Explanation:
Electric field due to a line charge is given by the expression
E = [/tex]
where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is
8.85 x 10⁻¹².
Putting the given values in the equation given above
E =
E = 1.655 x 10⁷ N/C