Question

A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is the coefficient of kinetic friction?

Answer 1

Answer:

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force,$F_x=\mu_kN$

Where $F_x$=Horizontal force

N=Normal force

$\mu_k$=Coefficient of kinetic friction

Substitute the values in the formula

$100=\mu_k(500)$

$\mu_k=\frac{100}{500}=0.2$

Hence, the coefficient of kinetic friction =0.2