Using the law of conservation of angular momentum, we have
<span>I1 w1 = I2 w2 </span>
<span>ie., m1r^2/2 x w1 = ( m1r^2/2 + m2r^2 ) w2 </span>
<span>ie., new angular velocity w2 = m1 w1 / ( m1+ 2m2) = 125 x 3.1 / ( 125 + 2 x39.5 ) </span>
<span>= 1.8995 = 1.9 rad /sec ( nearly )</span>
Heat energy required to increase the temperature of water in bathtub is 12,546,000 Joules.
<h3>What is thermal energy?</h3>
The energy contained by an object by virtue of heating is known as thermal energy.
Given is the mass of water m = 150 kg, Temperature change ΔT = (40 -20)= 20 °C
The specific heat of water Cp =4182 J/kg.°C
Heat transfer Q =m x Cp x ΔT
Q = 150 x 4182 x 20
Q = 12,546,000 J
Thus, Heat energy required to increase the temperature of water in bathtub is 12,546,000 Joules.
Learn more about thermal energy.
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Answer:
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Explanation:
The attraction will decrease. Hope I helped :)
