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inessss [21]
3 years ago
11

Given \qquad m \angle QPS = 107^\circm∠QPS=107 ∘ m, angle, Q, P, S, equals, 107, degrees \qquad m \angle RPS = 4x + 27^\circm∠RP

S=4x+27 ∘ m, angle, R, P, S, equals, 4, x, plus, 27, degrees \qquad m \angle QPR = 9x - 115^\circm∠QPR=9x−115 ∘ m, angle, Q, P, R, equals, 9, x, minus, 115, degrees Find m\angle QPRm∠QPRm, angle, Q, P, R:
Mathematics
2 answers:
guajiro [1.7K]3 years ago
7 0

Answer:

20°

Step-by-step explanation:

4x+27°+9x-115°=107°

4x+9x + 27°-115°=107°

13x-88°=107°

add 88 on both sides

13x=195°

divide 13 on both sides

x=15

9(15°)-115°

135°-115° = 20

The answer is 20

Ray Of Light [21]3 years ago
4 0

Answer:

25 degrees

Step-by-step explanation:

On Khan Academy the answer is 25 degrees, I put in 20 degrees at first and I was wrong, I clicked the get help button and that answer is actually 25 degrees.

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