The temperature at 5:00 am functions
1 answer:
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The equivalent resistance of a series circuit is found by finding the sum of the individual resistances
The series resistor required is <u>1.25 Ω</u>
The power rating of the resistor, is <u>2,000 W</u>
The reason why the above values are correct are as follows;
The given parameter are;
Applied DC Voltage, V = 250 V
The full load armature current, I = 50 A
Required reduced armature current, = 40 A
Solution:
First part
The resistance, <em>R</em>, of the circuit, is given as follows;
Therefore;
The voltage, V = I·R, therefore, with a series resistor, , we can have;
V = I·R = ·(
+ R) (given that the same current flows through both resistor)
Where the required current is = 40 A, we get;
Which gives;
The required series resistor, = <u>1.25 Ω</u>
Second part;
Power, P = I²·R
The power rating of the resistor, which is added to the circuit to regulate the current to 40A is therefore, given as follows;
=
²·
∴ = 40² × 1.25 = 2,000
The power rating of the resistor is <u>2,000 W</u>
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