If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
or 
Step-by-step explanation:
The lateral area of a cylinder is calculated by the following formula
Where r is the radius of the right cylinder and h is the height
In this case we know that the diameter d of the cylinder is
Therefore the lateral area is:
Answer:
x = 4
Step-by-step explanation:
<C = <A
25° = 8x - 7
32 = 8x
x = 4
Answer:
f ( - 2 ) = - 12
Step-by-step explanation:
f ( - 2 ) = - 3 ( -2 )^2
then you do the exponent first so
- 3 ( 4 )
now you multpily the - 3 and 4
you get - 12
Answer:
See explanation
Step-by-step explanation:
Consider triangles ABC and DEC. In these triangles,
- given
- given;
as vertical angles.
So,
by SAS postulate (two sides and angle between these sides of one triangle are congruent to two sides and angle between these sides of another triangle, so triangles are congruent).
Congruent triangles have congruent corresponding parts, hence,
