Answer:(Fog)(-6)=29
Step-by-step explanation:
(fog)=-3(2x+2)-1
=-6x-6-1
=-6x-7
(fog)(-6)= -6(-6)-7
=36-7
=29
Answer:
100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,001
Hope this helps!:)
h(t)=-16t²+32t+64
=-16(t²-2t)+64
=-16(t²-2t+1-1)+64
=-16(t-1)²+16+64
=-16(t-1)²+80
maximum value=80 and is obtained at t=1