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Natasha2012 [34]
3 years ago
11

13/4 + c = 3/4 what’s c,?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0

Answer:

c = -2.5

Step-by-step explanation:

13/4 + c =3/4

2.5 + c = 0

c=-2.5

Igoryamba3 years ago
3 0

Answer:

Step-by-step explanation:

13/4+c=3/4

C=3/4-13/4

C=2 1/2

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La base de una cartulina rectangular mide 8 cm de altura si le recortamos 3 cm a su altura el area de la nueva cartulina seria 1
aev [14]

Answer:

w=8cm\\h=18.75cm

Step-by-step explanation:

Let:

w=Width\\h=Initial\hspace{3}height\\h_m=Modified\hspace{3}height\\\\Where:\\\\h_m=h-3

The area of the cardboard can be calculated using the formula to find the area of a rectangle:

A=w*h

The area of the new cardboard would be:

A=w*h_m\\\\Where:\\\\w=8\\h_m=h-3\\A=126

So:

126=8*(h-3)\\\\126=8h-24

Solving for h:

126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm

Therefore, the dimensions of the initial cardboard are:

w=8cm\\h=18.75cm

<u><em>Translation:</em></u>

Sea:

w=Ancho\\h=Altura\hspace{3}inicial\\h_m=Altura\hspace{3}modificada\\\\Donde:\\\\h_m=h-3

El área de la cartulina se puede calcular usando la fórmula para encontrar el área de un rectángulo:

A=w*h

El área de la nueva cartulina sería:

A=w*h_m\\\\Donde:\\\\w=8\\h_m=h-3\\A=126

Entonces:

126=8*(h-3)\\\\126=8h-24

Resolviendo para h:

126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm

Por lo tanto, las dimensiones de la cartulina inicial son:

w=8cm\\h=18.75cm

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\displaystyle\int_0^1\int_0^x\int_0^{\sqrt{1-x^2}}z\,\mathrm dz\,\mathrm dy\,\mathrm dx

The same integral in the required order is

\displaystyle\int_0^1\int_0^{\sqrt{1-z^2}}\int_0^xz\,\mathrm dy\,\mathrm dx\,\mathrm dz

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Which of the following sequences is not arithmetic?
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Answer:

option c

Step-by-step explanation:

c doesnt follow a pattern

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Answer:

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