Please help me on this

Mathematics

1 answer:

AlekseyPX3 years ago

8 0

9514 1404 393

Answer:

10 ft

Step-by-step explanation:

The midsegment length is the average of the other two lengths.

(QR +PS)/2 = TU

QR +PS = 2×TU . . . . . . . . . . . . . . . multiply by 2

QR = 2×TU -PS = 2(14 ft) -18 ft . . . subtract PS; substitute given values

QR = 10 ft

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$\huge\fbox{Answer ☘}$

$\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3} \times - 1} = 2( \frac{32}{243} ) {}^{2x} }\\ \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times - 1 } = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x} \\\\ 3( \frac{3}{2} ) {}^{2 \times - 1} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{2}{3} ) {}^{2} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x} \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x = \frac{1}{5} }$