Y=-16t^2+8t

How can we write 4y = 5x - 12 in y = mx + b?

Y_Kistochka [10]

Answer:

$y=\frac{5}{4}x-3$

Step-by-step explanation:

Hope this helps!

=)

4 0

3 years ago

Read 2 more answers

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

3 years ago

Select the correct answer.

jenyasd209 [6]

The expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)

A cubic equation in algebra is a one-variable equation of the form ax3+bx2+cx+d=0 where an is nonzero. The roots of the cubic function defined by the left side of this equation are the solutions to this equation.

Given expression 2x³-3x²-3x+2 whose one of factor is (x-2)

We have to find second factor of given equation

First we will be rational root theorem to given expression so will get following expression:

$\left(x+1\right)\frac{2x^3-3x^2-3x+2}{x+1}$

So one factor is (x-1) and now simplifying $\frac{2x^3-3x^2-3x+2}{x+1}$ we get 2x² - 5x +2 and the factor of 2x² - 5x +2 will be (2x-1)(x-2)

Hence the expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)

Learn more about Polynomial here:

brainly.com/question/4142886

#SPJ10

4 0

1 year ago

John's temperature is 98.6 degrees.<br> Positive or Negative

Leto [7]

Answer:

positive, its above 0

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The surface area of a typical classroom floor is closest to______.

avanturin [10]

Answer would be C. Why A would be incorrect: 100m^2 is 100m × 100 m. That would be as big as a football field. Why B would be incorrect: 1cm^2 is 1cm × 1cm. You can use a regular 15 cm to measure a piece of paper with the length of 1cm each side. Why C would be correct: 1m^2 = 1m × 1m and it is also equals to 60cm × 60 cm. A 1 meter ruler = 60 cm = 4 times of your average 15 cm ruler. So, it is reasonable that a classroom is 10m by 10m in length and breadth. Why D would be incorrect: The same explanation applies to here as well. Things that can be measured with 1m × 1m is a square table so your classroom can't be that small to fit an average of 30 to 40 students in there. I hope my explanations were detailed and easy to understand. :)

4 0

2 years ago

Read 2 more answers