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MakcuM [25]
3 years ago
7

Think about a typical school day. In the space provided below, describe how each of the different forms of energy we have learne

d about (chemical, electrical, heat, kinetic, potential, and solar) are used during a typical school day and how each form of energy is transformed into another.
Physics
2 answers:
krok68 [10]3 years ago
6 0

Answer:

Explanation:

Chemical energy- A bunsen burner burning a beaker filled with water.

Heat energy- The water in the beaker absorbing the heat from the burner.

Electrical energy- Running Fans and lights in a classroom by switches.

Solar energy- Solar energy harnessed by solar panels to run the fans and lights by converting it into electrical energy.

Potential energy- A ball being held by a student at a certain height possesses energy due to gravity.

Kinetic energy- The same ball being left by the boy from a certain height produces kinetic energy

Nezavi [6.7K]3 years ago
3 0

Answer:

During a typical school day all forms of eneergy is being utilised and also transfer of energy takes place from one form to another.

Explanation:

Chemical energy- A bunsen burner burning a beaker filled with water.

Heat energy- The water in the beaker absorbing the heat from the burner.

Electrical energy- Running Fans and lights in a classroom by switches.

Solar energy- Solar energy harnessed by solar panels to run the fans and lights by converting it into electrical energy.

Potential energy- A ball being held by a student at a certain height possesses energy due to gravity.

Kinetic energy- The same ball being left by the boy from a certain height produces kinetic energy

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Water at 288.7 k flows through a 15.24-cm. diameter horizontal pipe into a 190-l drum. determine the minimum time it will take t
nikdorinn [45]

The flow will be laminar if Reynold's numberN_{R} is less than 2000.

Use the Reynold's formula and rearrange to calculate velocity of water in the pipe.

N_{R} = \frac{v D}{\nu}

Where, v is velocity of the fluid, D is the diameter of pipe, and \nu is the kinematic viscosity i.e. 1.12 \times 10^{-6} m^2/s for water at 288.7 K from Appendix.

So, velocity is:

v = \frac{N_{R} \nu}{D}

The flow rate <em>Q</em>:

Q = vA=v\pi D^2/4=\frac{\frac{N_R \nu}{D} \pi D^2}{4} =[tex] t = \frac{V}{\frac{N_R \nu \pi D}{4}} = \frac{4V}{N_R \nu \pi D} =\frac{4 \times 190 L\frac{10^{-3} m^3}{L}}{2000 \times 1.12\times 10^{-6} m^2/s \pi 15.24 cm\frac{1 m}{100 cm}}  = 2226.3 s \frac{1 min}{60 s}= 37.1 min [/tex]

Where A is the area of cross section of pipe.

The time taken to fill is:

t = Q/V

Where V is the capacity of the tank.


7 0
3 years ago
(a) What resonant frequency would you expect from blowing across the top of an empty soda bottle that is 18 cm deep, if you assu
V125BC [204]

Answer:

476.387 Hz

714.583 Hz

Explanation:

L = Length of tube

v = Speed of sound in air = 343 m/s

Frequency for a closed tube is given by

f=\dfrac{v}{4L}\\\Rightarrow f=\dfrac{343}{4\times 0.18}\\\Rightarrow f=476.389\ Hz

The frequency is 476.387 Hz

If it was one third full L=0.18-\dfrac{1}{3}0.18

f=\dfrac{v}{4L}\\\Rightarrow f=\dfrac{343}{4\times (0.18-\dfrac{1}{3}0.18)}\\\Rightarrow f=714.583\ Hz

The frequency is 714.583 Hz

5 0
3 years ago
determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if per
krok68 [10]

Answer:

-0.383 m

Explanation:

Diameter of cylinder = 4m  therefore  r = 2

height of cylinder ( H ) = 4 m

specific gravity = 0.6 ( assumed )

depth of immersion = 'h'

<u>Determine the metacentric height </u>

weight of cylinder in water = water displaced

= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h

= 0.6 * 4 = h

∴ h = 2.4 m

hence the depth of center of buoyancy from free space = h /2 = 1.2 m

The metacentric height can be calculated using the formula below

Gm = Io / Vsubmerged  - BG

attached below is the remaining solution

6 0
3 years ago
You are carrying a 7.0-kg bag of groceries as you walk at constant velocity along the sidewalk. You walk a distance of 82 meters
MAVERICK [17]

Answer:

0J

Option: B

Explanation:

Work is done when something is moved by the force in the direction of the force. That is the force (e.g., the weight) and the direction the object moves must be aligned for work to be done. In this given condition, the direction is horizontal and the force is downward as its gravity force. That 90° between the two vectors.

The work function is W = m × g ×h × cosθ

\text { Where, in this case theta }=90^{\circ}

Hence,  

Work done = 7 × 9.8 × 1.5 × cos(90)  

Work done = 0 (cos90^{\circ} = 0)

Work done = 0

Therefore work done is 0 J.

7 0
3 years ago
A space rover weighs less on Mars than it does on Earth. Which statement explains this difference? A. The gravitational constant
Maksim231197 [3]

Answer:

B. The mass of Mars is less than the mass of Earth.

Explanation:

Mass of an object is the constant anywhere in the universe.

The weight of an object is equal to the gravitational force acting on it.

Weight is given by

W=\dfrac{GMm}{R^2}\\\Rightarrow W=\dfrac{GM}{R^2}m\\\Rightarrow W=mg

where

G = Gravitational constant

M = Mass of Planet

R = Radius of planet

m = Mass of object

g = Acceleration due to gravity

So weight of an object depends on the acceleration due to gravity on that planet. The acceleration due to gravity depends on the mass and radius of the planet.

The weight of the object is less on Mars because mars has less mass compared to Earth.

6 0
3 years ago
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