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MakcuM [25]
3 years ago
7

Think about a typical school day. In the space provided below, describe how each of the different forms of energy we have learne

d about (chemical, electrical, heat, kinetic, potential, and solar) are used during a typical school day and how each form of energy is transformed into another.
Physics
2 answers:
krok68 [10]3 years ago
6 0

Answer:

Explanation:

Chemical energy- A bunsen burner burning a beaker filled with water.

Heat energy- The water in the beaker absorbing the heat from the burner.

Electrical energy- Running Fans and lights in a classroom by switches.

Solar energy- Solar energy harnessed by solar panels to run the fans and lights by converting it into electrical energy.

Potential energy- A ball being held by a student at a certain height possesses energy due to gravity.

Kinetic energy- The same ball being left by the boy from a certain height produces kinetic energy

Nezavi [6.7K]3 years ago
3 0

Answer:

During a typical school day all forms of eneergy is being utilised and also transfer of energy takes place from one form to another.

Explanation:

Chemical energy- A bunsen burner burning a beaker filled with water.

Heat energy- The water in the beaker absorbing the heat from the burner.

Electrical energy- Running Fans and lights in a classroom by switches.

Solar energy- Solar energy harnessed by solar panels to run the fans and lights by converting it into electrical energy.

Potential energy- A ball being held by a student at a certain height possesses energy due to gravity.

Kinetic energy- The same ball being left by the boy from a certain height produces kinetic energy

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A pilot who accelerates at more than 4 g begins to "gray out" but doesn’t completely lose consciousness. (a) Assuming constant a
Allushta [10]

Answer:

33.7410805301 s

22336.5953109 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 4\times 331

s = Displacement

a = Acceleration = 4g=4\times 9.81\ m/s^2

g = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{4\times 331-0}{4\times 9.81}\\\Rightarrow t=33.7410805301\ s

The time taken is 33.7410805301 s

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 9.81\times 33.7410805301^2\\\Rightarrow s=22336.5953109\ m

The plane would travel 22336.5953109 m

7 0
4 years ago
6. traction a. friction between a tire and the road.b. pushes a moving object out of a curve and into a straight linec. the abil
Gennadij [26K]

Answer:

6. a. friction between a tire and the road

7. c. energy of motion

8. c. the force with which a moving vehicle hits another object

Explanation:

6. As a car moves along the road, the tires push back against the ground. As tires push back against the ground, the road exerts and opposing force to the motion of the tires. This opposing force is the friction between the tires and the road. <u>This opposing force between the tires and the rad is called traction.</u>

So, the answer is a

7. As an object moves, it has energy. <u>This energy due to its motion is called kinetic energy.</u>

So, the answer is c

8. When a moving vehicle hits another object, it exerts a force on the object. The process of the vehicle hitting the other object is called impact and the<u> force exerted on the object is called the force of impact. </u>

So, the answer is c.

4 0
3 years ago
Suppose you have 600.0 grams of room temperature water (20.0 degrees Celsius) in a thermos. You drop 90.0 grams of ice at 0.00 d
IrinaK [193]

Answer:

T_{f} = 7.02 ° C

Explanation:

The liquid water gives heat to melt the ice (Q₁) maintaining the temperature of 0 ° C and then the two waters are equilibrated to a final temperature.

Let's start by calculating the heat needed to melt the ice

Q₁ = m L

Q₁ = 0.090 3.33 10⁵

Q₁ = 2997 10⁴ J

This is the heat needed to melt all the ice

Now let's calculate at what temperature the water reaches when it releases this heat

Q = M c_{e} (T₀ -T_{f})

Q₁ = Q

    T_{f} = T₀ - Q₁ / M c_{e}

T_{f} = 20.0 - 2997 104 / (0.600 4186)

T_{f}= 20.0 - 11.93

T_{f} = 8.07 ° C

This is the temperature of the water when all the ice is melted

Now the two bodies of water exchange heat until they reach an equilibrium temperature

Temperatures are

Water of greater mass     T₀₂ = 8.07ºC

Melted ice                         T₀₁ = 0ºC

M c_{e} (T₀₂ - T_{f}) = m c_{e} (T_{f} - T₀₁)

      M T₀₂ + m T₀₁ = m T_{f}+ M T_{f}

T_{f}= (M T₀₂ + 0) / (m + M)

T_{f} = M / (m + M) T₀₂

let's calculate

T_{f} = 0.600 / (0.600 + 0.090) 8.07

     T_{f} = 7.02 ° C

4 0
3 years ago
Name three ways electricity can be produced.​
Naya [18.7K]

Answer:

water

the sun

fossil fuels

7 0
3 years ago
A student sits at rest on a piano stool that can rotate without friction. the moment of inertia of the student-stool system is 4
stich3 [128]
<span>As we Know ω=v/r I2 = m*R² = 1.5*0.35² = 0.18375 kgâ™m² I = Is + I2 = 4.28375 kgâ™m² w = L/I = (v*R*m)/I = (2.8*0.35*1.5)/4.28375 = 0.343 rad/sec So the answer is 0.343 rd/sec</span>
7 0
4 years ago
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