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katrin [286]
3 years ago
15

The lower atmosphere is mostly warmed by radiated heat from Earth's surface. However, water heats up and cools down more slowly

than land. Knowing this, which of the following statements is most likely true?
A. On a cloudy day, the air over a northern section of the ocean will be warmer than the air over a southern section of the ocean.

B. On a sunny day, the air over a lake will be cooler than the air over the bordering land.

C. On a cloudy day, the air over a southern section of the ocean will be warmer than the air over a northern section of the ocean.

D. On a sunny day, the air over a piece of land will be cooler than the air over a bordering lake.
Physics
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

B

Explanation:

JulsSmile [24]3 years ago
6 0
The answer is B. On a sunny day, the air over a lake will be cooler than the air over the bordering land.
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2 years ago
In which situation is no work considered to be done by a force?
andre [41]
If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.
If the angle is 45, then there is still some work involved.
The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90. 
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3 years ago
The scientific method _____.
Lubov Fominskaja [6]
The answer is D I took the test
3 0
2 years ago
What is the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure
mezya [45]

Answer:

this is a no brainer

Explanation:

As air pressure in an area increases, the density of the gas particles in that area increases.

8 0
3 years ago
The predictions of Rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming a
Vera_Pavlovna [14]

Answer:

The radius of the gold nucleus is 7.1x10⁻¹⁵m

Explanation:

The nearest distance is:

r=\frac{kze^{2} }{mpV^{2} } (eq. 1)

Where

z = atomic number of gold = 79

e = electron charge = 1.6x10⁻¹⁹C

k = electrostatic constant = 9x10⁹Nm²C²

energy of the particle = 32 MeV = 5.12x10⁻¹²J

At the potential energy is zero, all the energy will be kinetic energy:

E_{k} =\frac{1}{2} m V^{2}

Where

m = 4 mp = mass of proton

5.12x10^{-12} =\frac{1}{2} *4*m_{p}* V^{2} \\m_{p}* V^{2} = 2.56x10^{-12}

Replacing in equation 1

r=\frac{9x10^{9}*79*(1.6x10^{-19})^{2}   }{2.56x10^{-12} } =7.1x10^{-15} m

8 0
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