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Alinara [238K]
3 years ago
12

Assume you are in the car and the car is moving at a certain speed to

Physics
1 answer:
Setler79 [48]3 years ago
6 0
You are at rest with respect to the car.
You are in motion with respect to the School.

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A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
In which scenario does radiation occur? warming soup on a stove drying towels at the beach cooking eggs in boiling water warming
shepuryov [24]

Answer: drying towels at the beach.

Explanation:

Radiation simply has to do with the energy that is gotten from a particular source and then goes through some materials. It simply means the way energy is being transmitted as waves or heat through a certain medium.

From the options given, the scenario whereby a radiation takes place is when drying towels on the beach.

8 0
3 years ago
Read 2 more answers
Consider the sections of two circuits illustrated above. Select True or False for all statements. After connecting c and d to a
Basile [38]

Answer:

Follows are the solution to the given question:

Explanation:

In this question the missing file of the circuit is not be which is defined in attached file please find it.

In Option 1, this statement is true because the current is on R_3 \  and \ R_4, that is the same.

In option 2, this statement is false because Rcd=R_3+R_4 therefore it implies that Rcd is always larger then R_3.

In option 3,  this statement is true because the voltage of R_1 \ and \ R_2 is always equal.

In option 4, this statement is true because Rab= \frac{1}{(\frac{1}{R1}+\frac{1}{R2})}=\frac{R1R2}{(R1+R2)}. \frac{R2}{(R1+R2)}is always smaller then 1 therefore,R_1 \times (\frac{R2}{(R1+R2)}) is always equal to R1.

5 0
3 years ago
Solve for y<br>11=y/3+7​
butalik [34]

Answer:

Explanation:

11 = y/3+7

collecting like terms

11 - 7 = y/3

4 = y/3

multiplying both sides by 3 gives us

12 = y

therefore

y = 12

3 0
3 years ago
If a person does 20 J of work on a book in 10 seconds, how powerful was the person while doing the work?
Korolek [52]

Answer:

2 W

Explanation:

P = W/t

= 20 J / 10 s

= 2 W

4 0
2 years ago
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