An external force of 5N is applied to a go-kart that is opposite it’s direction of travel for 5 seconds. What is the resulting m
omentum of the go-kart?
Options:
A: 25 kg m/s
B: 100 kg m/s
C: 975 kg m/s
1 answer:
Answer:
25N.s=25kgm/s
Explanation:
The resulting momentum in this case is equal to the impulse created by the force 5N during 5 seconds
ΔP=Force.time=F.t
= 5x5=25kgm/s
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