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GaryK [48]
3 years ago
14

Find two numbers that Multiply to -40 and add to 6

Mathematics
2 answers:
Tanzania [10]3 years ago
8 0
Reorder the terms: 6.25 + -5y + y^2 = -14 + 6.25

Combine like terms: -14 + 6.25 = -7.75 6.25 + -5y + y2 = -7.75

Factor a perfect square on the left side: (y + -2.5)(y + -2.5) = -7.75

Can't calculate square root of the right side (negative). The solution to this equation could not be determined.
Cerrena [4.2K]3 years ago
3 0
X * y = -40
X + y = 6
I believe it would be -4 and 10
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Expand and simplify this equation plz, 4(3x+5) - 5(8x+2)
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4(3x + 5) - 5(8x + 2) \\ 12x + 20 - 40x - 10 \\ 12 x - 40x + 20 - 10 \\  - 28x + 10

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A water hose had filled up 1⁄3 of a pool after 1⁄2 of an hour. At this rate, how many hours would it take to fill the pool?
Vlad1618 [11]

\huge{ \rm{Question:}}

A water hose had filled up 1⁄3 of a pool after 1⁄2 of an hour. At this rate, how many hours would it take to fill the pool?

\huge{ \rm{Answer:}}

It takes 1.5 hours or 1 hour and 30 min. to fill the pool.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Please is urgent please
Tcecarenko [31]

Answer: Assuming the plumber will round up the hours, the answer is 335.

Step-by-step explanation:

You can use this equasion to solve the problem: 75+52x=c

In this case, x would equal the number of hours he would work and c would represent the final cost.

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3 0
3 years ago
Which angle in the figure is a right angle?
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2 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
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