Answer:
32.4 mol
Explanation:
Given data:
Number of moles of C atom present = ?
Number of moles of glucose = 5.4 mol
Solution:
Glucose formula = C₆H₁₂O₆
There are 6 moles of C atoms are present in one mole of glucose.
In 5.4 moles of glucose:
5.4 mol × 6 = 32.4 mol
Cumulus, stratus, and cirrus, there's many more but these are the main ones ^^
PH + poH = 14
6.2 +poH = 14
poH = 7.8
Answer: The equilibrium constant for the given reaction is 0.0421.
Explanation:
Concentration of ![[PCl_5]](https://tex.z-dn.net/?f=%5BPCl_5%5D)
= 0.0095 M
Concentration of ![[PCl_3]](https://tex.z-dn.net/?f=%5BPCl_3%5D)
= 0.020 M
Concentration of ![[Cl_2]](https://tex.z-dn.net/?f=%5BCl_2%5D)
= 0.020 M
The expression of the equilibrium constant is given as:
![K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020 M}{0.0095 M}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D%3D%5Cfrac%7B0.020%20M%5Ctimes%200.020%20M%7D%7B0.0095%20M%7D)
(An equilibrium constant is an unit less constant)
The equilibrium constant for the given reaction is 0.0421.
It would be endothermic because the log is in the system.
