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Drupady [299]
3 years ago
7

How does a solution with a pH of 2 compare to a solution with a pH of 1?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
5 0
I’m going to go with The pH 1 solution is two times more acidic than that with a pH of 1. If that’s not the answer, then my second best guess would be The pH solution is ten times more acidic than that with a pH of 2.

The first and third answer choice wouldn’t even be an answer so you can just cancel those two out and pick between answer choice 2 or 4.

Hope this helps, and have an amazing day!! :))
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10. The density of aluminum is 2.7 g/cm². A 27g piece of aluminum will have<br> what volume?
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27g x 1cm^2/2.7g = answer in cm^2
Grams cancel out
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3 years ago
Aluminium +hydrochloride acid ________+_________​
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Answer:

Aluminium Chloride + Hydrogen

Please vote for Brainliest and I hope this helps!

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Question #1: Identify the type of Mutation below
borishaifa [10]

Answer:

Deletion

Explanation:

A mutation refers to a change in the DNA sequence. This means that the original sequence of bases in the DNA has been altered permanently.

There are three types of DNA mutations;  base substitutions, deletions and insertions.

In the particular case of this question, the original is TTCGATA while the copy is TTGATA. If you look closely at the two, you will notice that the C has been omitted. This is an example of  deletion.

5 0
3 years ago
The process that makes atmospheric nitrogen available to plants by mutualistic and free-living bacteria is called
artcher [175]
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3 0
3 years ago
A first-order reaction is 45% complete at the end of 43 minutes. What is the length of the half-life of this reaction
shtirl [24]

The half-life of the reaction is 50 minutes

Data;

  • Time = 43 minutes
  • Type of reaction = first order
  • Amount of Completion = 45%

<h3>Reaction Constant</h3>

Let the initial concentration of the reaction be X_0

The reactant left = (1 - 0.45) X_0 = 0.55 X_0 = X

For a first order reaction

\ln(\frac{x}{x_o}) = -kt\\ k = \frac{1}{t}\ln (\frac{x_o}{x}) \\ k = \frac{1}{43}\ln (\frac{x_o}{0.55_o})\\ k = 0.013903 min^-^1

<h3>Half Life </h3>

The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.

x = \frac{x_o}{2} \\t = t_\frac{1}{2} \\t_\frac{1}{2} = \frac{1}{k}\ln(\frac{x_o}{x_o/2})\\

Substitute the values

t_\frac{1}{2} = \frac{1}{k}\ln(2)=\frac{0.6931}{0.013903}\\t_\frac{1}{2}= 49.85 min = 50 min

The half-life of the reaction is 50 minutes

Learn more on half-life of a first order reaction here;

brainly.com/question/14936355

4 0
2 years ago
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