Given :
A 10.99 g sample of NaBr contains 22.34% Na by mass.
To Find :
How many grams of sodium does a 9.77g sample of sodium bromine contain.
Solution :
By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.
Therefore , percentage of Na by mass in NaBr will be same for every amount .
Percentage of Na in 9.77 g NaBr is 22.34 % too .
Gram of Na = 
.
Hence , this is the required solution .
Answer:
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
Where,
is the enthalpy change
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of object = 36.2 g
Specific heat = 12.5 J/g°C
So,
one mole of sulfuric acid will contain 2 moles of hydrogen atoms. The molar mass of sulfuric acid is 98.0795 g/mol. This means that every mole of sulfuric acid has a mass of 98.0795 g. Since you're dealing with one mole of sulfuric acid, it follows that you will also be dealing with two moles of hydrogen.
3 Sig FIgs in 303,000 mm
Any nonzero is a sig fig.
Any zero between two non zeros is a sig fig.
The molality of the solution is a measure of its concentration that can be calculated by dividing the amount of substance in moles by the amount of the solvent in kilograms. Mathematically, this can be expressed as that of the equation below.
molality = amount of solute (mole) / amount of solvent (kg)
molality = 5 moles / 3.2 kg
molality = 1.5625 m
Rounding off the answer to the nearest tenths, will give the final answer of <em>1.6 m</em>.
