We use one concept of colligative properties which is freezing point depression. We solve it as follows:
ΔTf = kf (m) where kf is the freezing point depression constant and m is the molality of the solution
m = n solute / m solvent = 10.20 g (1 mol / 180.18 g ) / .355 kg = 0.16 mol/kg
ΔTf = kf (m)
ΔTf = -1.86 (0.16) = - 0.2976 °C
Hope this answers the question.
Answer:
plant respiration shows arrows where CO2 is released.the arrow is going out of the trees represent the release of carbon dioxide.the arrows from the factories,clouds,water shows the circulation of carbon.
The answer is A carbon monoxide.
а о
Explanation:
The given cation:
(Rf₂Al₂F₃)³⁺
The oxidation number gives the extent to which a specie is oxidized in a reaction.
This number is assigned based on some rules:
- Elements in combined state whose atoms combines with themselves have an oxidation number of zero.
- The charge carried on simple ions gives their oxidation number.
- Algebraic sum of all the oxidation numbers of atoms in neutral compound is zero. In an ion with more than one kind of atom, the charge on it is the oxidation number.
for the specie given;
Known:
oxidation number of Al = +3
F = -1
charge = +3
let the oxidation number of Rf = k
2k + 2(3) + 3(-1) = +3
2k + 6 - 3 = 3
2k = 0
k = 0
The oxidation state of rutherfodium is 0
learn more:
Oxidation state brainly.com/question/10017129
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Oxygen and carbon are element combinations that will most likely form polyatomic ions.