Answer:
The constant density decreases
Explanation:
As the temperature of a solvent increases, the solubility of any gas dissolved in that solvent decreases.
For example:
when the temperature of a river, lake or stream is raised high , due to discharge of hot water from some industrial process the solubility of the oxygen in the water is decreased .The fish and the other organisms that live in the water bodies such as rivers, ponds, lakes etc can survive only in the presence of oxygen and decrease in the concentration of the water due to increased temperature can lead to the death of the fish and this may in turn damage the ecosystem.
In the above example, water is considered as the solvent and the oxygen is considered as the solute. When the temperature of the solvent that is water increases, the solubility of the gas that is oxygen in the solvent decreases.
Therefore the answer is decreases
Answer:
0.808 M
Explanation:
Using Raoult's Law

where:
= vapor pressure of sea water( solution) = 23.09 mmHg
= vapor pressure of pure water (solute) = 23.76 mmHg
= mole fraction of water
∴






------ equation (1)
------ equation (2)
where;
number of moles of sea water
number of moles of pure water
equating above equation 1 and 2; we have :



NOW, Molarity = 



As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have 
Answer:
<em><u>V = 25 m/s</u></em>
Explanation:
From first equation of motion, V = U + at
V = 10 + ( 5×3 )
V = 25 m/s
Answer:
I don’t know what recording station you’re referring to but, When seismic waves reach the seismograph, a graphical record, or seismogram, is produced
Explanation:
Answer:
Four (4) hydrogen atoms
Explanation:
C=C-C(triple bond)C
only four hydrogen atoms can bond with the vacant space