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UkoKoshka [18]
3 years ago
12

20g of butanedioic acid were shaken with a mixture of 100 cm3 ether and 100 cm3 water at 298K. After titration with standard sod

ium hydroxide, it was noted that the ether layer needed 12.4mL of 0.2 mol dm-3 solution for complete neutralisation. Calculate the partition co-efficient.
Chemistry
1 answer:
zlopas [31]3 years ago
8 0

Answer:

I'm Not Good At Chemistry.

Explanation: It's Hard.

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How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut
san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = <em>8 = Concentration in Ethyl acetate / Concentration in water</em>

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

<em>Where X is the amount of material in grams that comes to the organic phase.</em>

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

<em>Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.</em>

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

<em>In the second extraction, you will extract 0.50g of material</em>

Thus, after the two extraction you will lost:

4.44g + 0.50g = <em>4.94g of material</em>

<em></em>

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3 years ago
The pressure of a gas sample at 60.0 °C is decreased from 3.40 atm to 2.60 atm by cooling at a constant volume. What is the temp
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Which element has the electron configuration 2-4?
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Carbon has the electronic configuration 2,4
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Which of the following
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Fe2O3 is the major component in rust. How many atoms are in one molecule of rust? A. 1 B. 2 C. 3 D. 5
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The correct option is D.

The major component of rust is Fe2O3. To know the number of atom in one molecule of rust, one have to look at the chemical formula of rust and determine the different atoms that are present and their numbers. Looking at the chemical formula above, one will notice that, two atoms of iron is present and three atoms of oxygen. The number of atoms present are written in front of the chemical symbol of each element. two atoms of iron added to three atoms of oxygen will give 5 atoms. Thus, five atoms are present in one molecule of rust.

8 0
3 years ago
Read 2 more answers
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