Answer: The molar mass of the unknown compound is 200 g/mol
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for molecular compound)
= freezing point constant = 
m= molality
Weight of solvent (benzene)= 0.250 kg
Molar mass of solute = M g/mol
Mass of solute = 26.7 g
Thus the molar mass of the unknown compound is 200 g/mol
Answer:
The sun is not yellow.
Explanation:
sun can look yellow or red whenever we see the sunlight at sunrise or sunset, when it becomes low on the horizon. That's only how the wavelengths of the low frequency (green , blue, magenta) are dispersed across the planet's crust, just as the tiny waves are distributed along the sea by huge rocks.
Answer:
18 DAYS IS THE HALF LIFE OF THE RADIOISOTOPE.
Explanation:
Using the formula
Nt = No * (1/2)^t/t1/2
where;
Nt = amount remaining = 25 g
No = Initial amounrt of the radioisotope = 50 g
t = time elapsed = 18 days
t1/2 = half life = unknown
Substitute the values into the equation and obtain the half life of the radioisotope;
Nt = No * (1/2) ^t/t1/2
25 = 50 * (1/2) ^18/t1/2
25 /50 = (1/2)^18/ t1/2
1/2 = (1/2)^18/t1/2
1/2)^1 = (1/2)^18/t1/2
1 = 18/t1/2
t1/2 = 18 days.
So therefore the half life of the radioisotope is 18 days.
The number of electrons per second passing an ammeter if it reads 10 nA is 6.24 × 10⁹ electrons per second
Since our current reads 10 nA and we require the number of electrons per second passing through the ammeter, 10 nA = 1 × 10⁻⁹ C/s.
Since there are 1.602 × 10⁻¹⁹ C/electron, the number of electrons per second, n = current/electron charge
= 1 × 10⁻⁹ C/s ÷ 1.602 × 10⁻¹⁹ C/electron
= 1/1.602 × 10¹⁰ electrons
= 0.62422 × 10¹⁰ electrons per second
= 6.2422 × 10⁹ electrons per second
≅ 6.24 × 10⁹ electrons per second
So, the number of electrons per second passing an ammeter if it reads 10 nA is 6.24 × 10⁹ electrons per second
Learn more about electrons passing per second here:
brainly.com/question/14959684
There has to be a force in order for it to move
In other words every action needs a reaction and vice versa
