Answer:
an uneven charge between the oxygen molecule and 2 hydrogen molecules
Explanation:
Moles of solute for both a and b are the same = 1 mol
<h3>Further explanation</h3>
Given
a 500 cm³ of solution, of concentration 2 mol/dm³
b 2 litres of solution, of concentration 0.5 mol/dm³
Required
moles of solute
Solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution
Can be formulated :

a.
V = 500 cm³ = 0.5 L
M = 2 mol/L
n=moles = M x V
n = 2 mol/L x 0.5 L
n = 1 mol
b.
V = 2 L
M = 0.5 mol/L
n=moles = M x V
n = 0.5 mol/L x 2 L
n = 1 mol
Answer:
0.00731 kg
Explanation:
Given that solution is a product of solute and solvent.
Hence, solution = solute * solvent
In this case, the solution is given as 0.950 grams = 0.00095 kilograms
solute is given as 130 grams = 0.13 kilograms
Hence to get the amount of solvent in kilograms, we have
Solution ÷ Solute => 0.00095 ÷ 0.13
= 0.0073076923
=> 0.00731 kilograms
B. is the right option. hope it will help you!