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Nonamiya [84]
3 years ago
12

A test of an automobile engine’s exhaust revealed that 3.5 g of NO2 was emitted in 10. minutes of operation. How many moles of N

O2 would this engine release if it were used for a 40.-minute commute, assuming that this measured number is representative of the emission under all circumstances?
Chemistry
1 answer:
kherson [118]3 years ago
5 0

Answer:

0.304 moles of NO₂ may be produced

Explanation:

During 10 minutes of operation, 3.5 g of NO₂ were produced by the engine.

In 40 minutes, the engine may produce (40 . 3.5)/ 10 = 14 g of gas

Solved by a rule of three.

Let's convert the mass to moles → 14 g . 1 mol/ 46 g = 0.304 moles

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Answer:

FALSE.

Explanation:

The right answer is false. There are three different groups of phylum for worms.

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How many grams of carbon dioxide are produced when 16 g of methane and 48 g of oxygen gas combust
larisa [96]
I believe the correct answer is 11 g
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2 years ago
Can someone please help me?
Olin [163]

Answer:

c.)the reactants have the same mass as the products

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

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3 years ago
How much heat is released at constant pressure if a 10.0 L tank containing 87.0 atm of hydrogen sulfide gas condenses at its boi
harina [27]

Answer:

929.4 kJ of heat is released.

Explanation:

The enthalpy of vaporization of hydrogen sulfide is 18.7 kJ/mol at -60.0 °C.

The data explains that 1 mol of H₂S uses 18.7 kJ of energy in vaporization.

By the Ideal Gas Law, we can know, how many moles do we have, of gas.

P. V = n . R . T

87 atm . 10L = n . 0.0821 L.atm/K.mol . 213 K

(87 atm . 10L) / (0.0821 K.mol/L.atm . 213 K) = 49.7 moles

1 mol ____ 18.7 kJ

49.7 moles _____ (49.7 . 18.7) = 929.4 kJ

3 0
3 years ago
Vanadium (III) hydroxide reacts with hydrobromic acid according to the following balanced chemical equation: V(OH)3 (s) + 3 HBr
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Answer:

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Explanation:

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2 years ago
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