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Nonamiya [84]
2 years ago
12

A test of an automobile engine’s exhaust revealed that 3.5 g of NO2 was emitted in 10. minutes of operation. How many moles of N

O2 would this engine release if it were used for a 40.-minute commute, assuming that this measured number is representative of the emission under all circumstances?
Chemistry
1 answer:
kherson [118]2 years ago
5 0

Answer:

0.304 moles of NO₂ may be produced

Explanation:

During 10 minutes of operation, 3.5 g of NO₂ were produced by the engine.

In 40 minutes, the engine may produce (40 . 3.5)/ 10 = 14 g of gas

Solved by a rule of three.

Let's convert the mass to moles → 14 g . 1 mol/ 46 g = 0.304 moles

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What is the net ionic equation of the reaction of mgso4 with sr(no3)2?
Bad White [126]

Balanced chemical reaction:  

MgSO₄(aq) + Sr(NO₃)₂(aq) → Mg(NO₃)₂(aq) + SrSO₄(s).

Ionic reaction:  

Mg²⁺(aq) + SO₄²⁻(aq) + Sr²⁺(aq) + 2NO₃⁻(aq) → Mg²⁺(aq) + 2NO₃⁻(aq) + SrSO₄(s).

Net ionic reaction:

Sr²⁺(aq) + SO₄²⁻(aq) → SrSO₄(s).

Magnesium sulfate (MgSO₄), strontium nitrate (Sr(NO₃)₂ and magnesium nitrate (Mg(NO₃)₂) are soluble in water. Strontium sulfate (SrSO₄) is not soluble in water.

This chemical reaction is double displacement reaction - cations and anions of the two reactants switch places and form two new compounds.


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3 years ago
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In studying effects of collisions between galaxies, astronomers usually make use of space telescopes.

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6 0
2 years ago
A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch
ivanzaharov [21]

Answer:

The reactions free energy \Delta G = -49.36 kJ

Explanation:

From the question we are told that

      The pressure of (NO) is P_{NO} = 9.20 \ atm

      The  pressure of  (Cl) gas is  P_{Cl} = 9.15 \ atm

       The  pressure of nitrosly chloride (NOCl) is P_{(NOCl)} = 7.70 \ atm

The reaction is

              2NO_{(g)} + Cl_2 (g)    ⇆   2 NOCl_{(g)}

 From the reaction we can  mathematically evaluate the \Delta G^o (Standard state  free energy ) as

                    \Delta G^o = 2 \Delta G^o _{NOCl} -   \Delta G^o _{Cl_2}  - 2 \Delta G^o _{NO}

The Standard state  free energy for NO is  constant with a value  

                 \Delta G^o _{NO} = 86.55 kJ/mol

 The Standard state  free energy for Cl_2 is  constant with a value                  

             \Delta G^o _{Cl_2} = 0kJ/mol

 The Standard state  free energy for NOCl is  constant with a value

         \Delta G^o _{NOCl} =66.1kJ/mol

Now substituting this into the equation

        \Delta G^o = 2 * 66.1 - 0 - 2 * 87.6

                = -43 kJ/mol

The pressure constant is evaluated as

         Q =  \frac{Pressure \ of  \ product }{ Pressure  \ of \ reactant }

Substituting  values  

        Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}

           = 0.0765

The free energy for this reaction is evaluated as

           \Delta  G  =  \Delta  G^o  + RT ln Q

Where R is gas constant with a value  of  R = 8.314 J / K \cdot mol

          T is temperature in K  with a given value of  T = 25+273 = 298 K

   Substituting value

                \Delta  G  = -43 *10^{3} + 8.314 *298 * ln [0.0765]

                       = -43-6.36

                      \Delta G = -49.36 kJ

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