Jasmine pushes an object a distance of 15 m at constant speed. It produces a 450J of work on the object. What strength Jasmine does it exert on the object?
Answer:
30J
Explanation:
Given parameters:
Distance moved = 15m
Work done = 450J
Unknown:
Strength Jasmine applied = ?
Solution:
The strength Jasmine applied or exerted on the object is the force of pull that cause the motion of the object and the distance it was moved.
Now;
Work done = Force x distance
So;
450 = Force x 15
Force = 
= 30J
Answer:
Robots will be created to allow scientists to use computer programs.
Explanation:
There are some other answers, but this one is more sufficient. :)
The neutralization reaction between potassium hydroxide and sulfuric acid is as follows
2KOH + H2SO4 ---> K2SO4 + 2H2O
number of moles of KOH= (43.74 x 0.500)/ 1000= 0.02187 moles
the reacting ratio of KOH to H2SO4 is 2:1 therefore the moles of H2SO4 is = 0.021187/2= 0.01094 moles
concentration(molarity) = ( 0.01094/50 ) x 1000= 0.2188M
False. Due to:
Entropy increases with molecular size (mass of compound)
HBr has greater molecular size (molar mass) than HCl
The value of standard entropy of HCl(g) is 187 joules/ kelvin
The value of standard entropy of HBr(g) is 199 joules / kelvin
When a physical change occurs, the arrangement of particles within the substance may change, but the atoms in the molecules remain bonded together.
