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Aleks04 [339]
3 years ago
13

Why is Nertic zone particularly rich in living things?

Chemistry
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

It is rich in organisms because sunlight passes through its shallow water enabling photosynthesis to occur.

Explanation:

I hope that helped!!

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What is the concentration, in grams per liter, of a solution prepared by dissolving 0.00040 mol HCl in 2.2 L H2O? Assume that th
Zolol [24]

Answer:

0.00663 grams/liter

Explanation:

HCl is a mineral acid with a molar mass of 36.46 g/mol.

No. of moles= mass/RMM

Making mass the subject of the formula:

Mass=Number of moles × RMM

Therefore 0.00040 mol HCl has a mass of:

0.00040 mol × 36.46 g/ mol

=0.01458 grams.

0.01458 grams are in 2.2 liters, Therefore 1 liter will have

0.01458 grams/2.2 liters= 0.00663 grams

concentration= 0.00663 grams/liter

4 0
3 years ago
Read 2 more answers
If vinegar is added to baking soda, the reaction Cu (s) + 2Ag(NO3) (aq) à 2Ag (s) + Cu(NO3)2 (aq) occurs. What evidence would in
Papessa [141]
The solution bubbles
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4 years ago
A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
6 0
3 years ago
13. What does 2n^2 stand for?
Sever21 [200]

Answer:

2n² is a formula that determines that the maximum number of electrons should be accommodated in a particular shell.

Explanation:

4 0
2 years ago
NEED HELP ASAFP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!PLEASE!
sp2606 [1]
Here to help! What’s up?
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